Question

我有一个帐户的ArrayList。带有A0001 ...和Z0001..I的帐户名称将此arraylist传递给api，需要使用Z200过滤名称并从列表中删除而不使用其他集合类。以下是我的课程

class Account {
private String accountName;
private long accountNumber;
private String accountType;

public String getAccountName() {
    return accountName;
}

public void setAccountName(String accountName) {
    this.accountName = accountName;
}

public long getAccountNumber() {
    return accountNumber;
}

public void setAccountNumber(long accountNumber) {
    this.accountNumber = accountNumber;
}

public String getAccountType() {
    return accountType;
}

public void setAccountType(String accountType) {
    this.accountType = accountType;
}

}

public class GenericTest {

public static List filterObjects(List accountList) {

    return list;
}

public static void main(String[] args) {
    List<Account> accList = new ArrayList<Account>();
    Account acc1 = new Account("A0001", 898989, "Savings");
    Account acc2 = new Account("A0002", 345126, "Current");
    Account acc3 = new Account("Z0001", 123467, "Savings");
    Account acc4 = new Account("Z0002", 879000, "Fixed");
    Account acc5 = new Account("Z0003", 898989, "Current");
    accList.add(acc1);
    accList.add(acc2);
    accList.add(acc3);
    accList.add(acc4);
    accList.add(acc5);

    GenericTest gt = new GenericTest();
    List<Account> filteredList = gt.filterObjects(accList);

    for (Account acc : filteredList) {
        System.out.println(acc.getAccountName());
    }
}

}

filterObjects api应该删除以Z开头的帐户对象并返回其他对象，而不使用api方法中的其他集合。我搜索了google和stackoverflow但没有找到合适的解决方案。请给我一些想法，这样我就可以工作了对那些人。提前谢谢。

Answer 1

循环集合并删除以Z开头的元素：

public static List<Account> filterObjects(List<Account> accountList) {
    for(int i = 0; i < accountList.size(); i++) {
        if(accountList.get(i).getAccountName().startsWith("Z")) {
            accountList.remove(i);
            i--; // Just removed an element, so jump back one index.
        }
    }
    return accountList;
}

或使用迭代器：

public static List<Account> filterObjects(List<Account> accountList) {
    for (Iterator<Account> iterator = accountList.iterator(); iterator.hasNext();) {
        Account account = iterator.next();
        if (account.getAccountName().startsWith("Z")) {
            iterator.remove();
        }
    }
}

需要api来删除使用特定charecter启动的对象，而不使用方法中的其他集合

1 个答案: