Question

我有一个json文件，该文件的数据格式如下：

{
    "rigidBodies": [
        {
            "name": "ball1.png", "imagePath": "ball1.png", "origin": {"x": 0, "y": 0},
            "polygons": [
                [
                    {"x": 0.16999998688697815, "y": 0.5724999904632568},
                    {"x": 0.16749995946884155, "y": 0.5324999690055847},
                    {"x": 0.16999998688697815, "y": 0.45250001549720764}
                ],
                [
                    {"x": 0.16999998688697815, "y": 0.45250001549720764},
                    {"x": 0.16749995946884155, "y": 0.375},
                    {"x": 0.2199999988079071, "y": 0.3725000023841858}
                ]
            ]
        }
    ]
}

我想在数组中推送数据，所以我尝试过这种方式，并说错误，

var poly = new Array();

    // note : parsing json 
    $.getJSON('my_assets/addPhysics/testPhysics.json', function(data) {
        //do stuff with your data here
             $.each(data, function(i, item) {
                   // for(var i=0;i<item[0].length;i++){
                        poly.push(item[0][i].x,item[0][i].y);
                    //}  
             });
    });

Answer 1

data是一个对象，您要循环的数组位于polygons数组内的rigidBodies属性中。你需要这样做：

var data = {
  "rigidBodies": [{
    "name": "ball1.png",
    "imagePath": "ball1.png",
    "origin": {
      "x": 0,
      "y": 0
    },
    "polygons": [
      [{
        "x": 0.16999998688697815,
        "y": 0.5724999904632568
      }, {
        "x": 0.16749995946884155,
        "y": 0.5324999690055847
      }, {
        "x": 0.16999998688697815,
        "y": 0.45250001549720764
      }],
      [{
        "x": 0.16999998688697815,
        "y": 0.45250001549720764
      }, {
        "x": 0.16749995946884155,
        "y": 0.375
      }, {
        "x": 0.2199999988079071,
        "y": 0.3725000023841858
      }]
    ]
  }]
}
var poly = [];

$.each(data.rigidBodies, function(i, body) {
  $.each(body.polygons, function(j, polygon) {
    $.each(polygon, function(k, coords) {
      poly.push([coords.x, coords.y]);
    });
  });
});

document.getElementById("output").innerHTML = JSON.stringify(poly);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="output"></div>

Answer 2

你应该试试这个 poly.push([item[0][i].x,item[0][i].y]); 所以poly [0] [0]是X
和poly [0] [1]是Y

如何在javascript中推送json数据？

2 个答案: