Question

我的Models.py如下所示。

class Payment(models.Model):
    payment_id = models.SmallIntegerField(primary_key=True)
    rental = models.ForeignKey('Rental', blank=True, null=True)
    amount = models.DecimalField(max_digits=5, decimal_places=2)
    payment_date = models.DateTimeField()

    def __unicode__(self):
       return u'%s' % (self.amount)

class Rental(models.Model):
    rental_id = models.AutoField(primary_key=True)
    inventory = models.ForeignKey(Inventory)

    def __unicode__(self):
       return u'%s' % (self.rental_id)

class Inventory(models.Model):
    inventory_id = models.AutoField(primary_key=True)
    film = models.ForeignKey(Film)
    store = models.ForeignKey('Store')
    last_update = models.DateTimeField()

    def __unicode__(self):
        return u'%s' % (self.amount)

我尝试使用以下代码显示给定rental_id的{{1}}和payment：

film_id

并且我很少得到预期的结果，如下所示：

for i in Rental.objects.filter(inventory__film_id=2).order_by("inventory_id"):
    amnt=Payment.objects.filter(rental_id= int(i.rental_id))
    print ("Rental of %s is %s") %(i, amnt)

帮我删除最终结果中的对象名Rental of 10310 is [<Payment: 4.99>] Rental of 13421 is [<Payment: 4.99>] Rental of 4364 is [<Payment: 4.99>] Rental of 7733 is [<Payment: 9.99>] Rental of 15218 is [<Payment: 9.99>]

预期结果：

Payment

Answer 1

for i in Rental.objects.filter(inventory__film_id=2).order_by("inventory_id"):
    amnt=Payment.objects.filter(rental_id= int(i.rental_id))
    print ("Rental of %s is %s") %(i, amnt[0].amount)

由于付款对象已退回给您，您必须提及要显示的字段。

删除循环中的模型名称Django ORM

1 个答案: