Question

好的，更容易阅读代码版本（我希望）

class First
  attr_accessor :addresses

  def initialize

    address

  end


  def address

        @addresses= []

      File.open("/RubyDev/useful/lib/list/listtest.txt").each_line do |i|

        @addresses << i.chomp

          end
  end

end

  class Server1
     b = Last.new
    puts "Im Server1"
    puts "Sending the following address to: #{b.loopaddress}"
  end

   class Server2
     b = Last.new.loopaddress
    puts "Im Server2"
     puts "Sending the following address to: #{b.loopaddress}"
  end

class Last
  n=First.new

  email_servers=[Server1.new,Server2.new]

  def loopaddress
  n.addresses.each_with_index do |i|
            i % email_servers.length
          end

  end

end

只是尝试在两台服务器之间一次一个地分配循环地址。感谢

Answer 1

这个算法应该有效：

#!/usr/bin/ruby1.8

addresses = (1..10).to_a    # Your list of addresses goes here
servers = (1..2).to_a       # Your list of servers goes here
addresses.each.with_index do |address, i|
  server = servers[i % servers.length]
  puts "Sending address #{address} to server #{server}" 
end

# => Sending address 1 to server 1
# => Sending address 2 to server 2
# => Sending address 3 to server 1
# => Sending address 4 to server 2
# => Sending address 5 to server 1
# => Sending address 6 to server 2
# => Sending address 7 to server 1
# => Sending address 8 to server 2
# => Sending address 9 to server 1
# => Sending address 10 to server 2

编辑补充说：我不会因为“课程很好，m'kay而创建更多课程”。我这样做是因为，例如，一个方法将一个对象作为其参数并在该对象上重复操作;该方法可能应该移动到该对象。也就是说，地址可能是它自己的对象：

class Addresses

  def initialize
    @addresses = (1..10).to_a    # Or read from a file, or whatever
  end

  def send_to_servers(servers)
    @addresses.each.with_index do |address, i|
      server = servers[i % servers.length]
      puts "Sending address #{address} to server #{server}"
    end
  end

end

servers = (1..2).to_a       # Your list of servers goes here
addresses = Addresses.new
addresses.send_to_servers(servers)

ruby循环到类问题

1 个答案: