Question

嘿，我正在测试PHP中的一些OPP原则

我创建了一个带有一个需要两个参数的方法的类。

当我实例化一个类并使用参数数据调用该方法时，我什么也得不到。

<?php

class example
{
    public $request;

    public function test($uprn, $sourceChannel)
    {
        $this->request = new stdClass();
        $this->request->uprn = $uprn;
        $this->request->sourceChannel = $sourceChannel;

    }

}

$test = new example();
$test->test('1', '2');

var_dump($test);die;

我在浏览器中获得的是一个像这样的空对象：

object(example)#1 (0) { }

但我希望如此：

object(example)#1 (2) { ["uprn"]=> string(1) "1" ["sourceChannel"]=> string(1) "2" }

知道我哪里错了......？

Answer 1

> stdClass is PHP's generic empty class, kind of like Object in Java or object in Python (Edit: but not actually used as universal base class; thanks @Ciaran for pointing this out). It is useful for anonymous objects, dynamic properties.

    You can get desired output just like this. 

  $request = new stdClass();
    $request->uprn = $var1;
    $request->sourceChannel = $var2;
    var_dump($request);die; 


    please go through this link to understand Generic empty class(stdClass).
    http://krisjordan.com/dynamic-properties-in-php-with-stdclass

    In PHP OOPS you can get the output as given below 
    class example
    {
        var $uprn,$sourceChannel; 

        public function test($uprn, $sourceChannel)
        {        
            $this->uprn = $uprn;
            $this->sourceChannel = $sourceChannel;
        }}

    $test = new example();
    $test->test('1', '2');
    var_dump($test);die;


    To understand much better go through this 
    http://php.net/manual/en/language.oop5.php

    Thanks

实例化一个类并使用方法填充对象

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