Question

在那里我创建了这个函数，如果有用户名那么在表中找到密码！

但是我收到了这个错误：

protected function checkLogin()
        {
            $conn = $this->connectDB();
            $password = mysqli_real_escape_string($conn, trim($_SESSION["password"]));
            $username = mysqli_real_escape_string($conn, trim($_SESSION["username"]));

        $conn = $this->connectDB();
                $record = mysqli_fetch_assoc(mysqli_query($conn, "SELECT * FROM profile WHERE email = '".$username."' OR cellphone = '".$username."' OR username = '".$username."'"));      

        if ($conn->error) 
        {
            echo $conn->error;
            $conn->close();
            return false;
        }
        $record = $record['password'];
        $conn->close();
        if($this->matchPasswords($record['password']))
            return true;
        return false;       
    }

错误：

（！）警告：非法字符串偏移＆＃39;密码＆＃39;在第383行的F：\ wamp \ www \ myweb \ libs \ core.php

我错了什么？

Answer 1

$record = $record['password'];
$conn->close();
if($this->matchPasswords($record['password']))

最有可能$record现在是一个字符串，但不是一个数组。

Answer 2

>  $record = mysqli_fetch_assoc(mysqli_query($conn, "SELECT * FROM
> profile WHERE email = '".$username."' OR cellphone = '".$username."'
> OR username = '".$username."'"));

返回一个关联表，为什么要执行此操作$record = $record['password'];？

尝试通过函数print_r

显示内容

mysqli中mysqli_fetch_assoc的非法字符串偏移量

2 个答案: