Question

示例文字文件：

["abc","123","apple","red","<a href='link1'>zzz</a>"],

["abc","124","orange","blue","<a href='link1'>zzz</a>"],

["abc","125","almond","black","<a href='link1'>zzz</a>"],

["abc","126","mango","pink","<a href='link1'>zzz</a>"]

预期输出：

abc 123 apple red 'link1'>zzz

abc 124 orange blue 'link1'>zzz

abc 125 almond black 'link1'>zzz

abc 126 mango pink 'link1'>zzz

我只是希望文件没有大括号，逗号用空格分隔，并且只获取行中最后一个元素的链接。

我尝试在Python中使用Lists。

我不知道如何继续。猜猜，我在某个地方出错了。帮助将不胜感激。在此先感谢：）

import sys
import re

Lines = [Line.strip() for Line in open (sys.argv[1],'r').readlines()]



for EachLine in Lines:
    Parts = EachLine.split(",")
    for EachPart in Parts:

        EachPart = re.sub(r'[', '', EachPart)
        EachPart = re.sub(r']', '', EachPart)

Answer 1

如果您打算使用正则表达式删除[和]，则需要转义方括号以将它们作为文字符号进行匹配。他们是特殊的＆＃34;表示字符类边界的正则表达式字符因此需要特殊处理。

以下是正则表达式替换示例：

EachPart = re.sub(r'[\[\]]', '', EachPart)

请参阅demo

但是，您可以使用不需要正则表达式的str.replace(old, new[, max])删除它们：

EachPart = EachPart.replace('[', '').replace(']', '')

请参阅demo

Answer 2

这可以使用以下脚本完成：

import csv
import re

with open('input.txt', 'r') as f_input, open('output.txt', 'w') as f_output:
    csv_input = csv.reader(f_input, delimiter='"')
    for cols in csv_input:
        if cols:
            cols = [x for x in cols[1:-1:2]]
            link = re.search(r"('.*?)<", cols[-1])
            if link:
                cols[-1] = link.group(1)

            f_output.write('{}\n'.format(' '.join(cols)))

这将为您提供output.txt包含：

abc 123 apple red 'link1'>zzz
abc 124 orange blue 'link1'>zzz
abc 125 almond black 'link1'>zzz
abc 126 mango pink 'link1'>zzz

更新 - 此代码的简化版本在repl.it上运行，以显示正确的输出。输入来自字符串，并显示输出。只需点击Run按钮。

更新 - 已更新以跳过空白行

Answer 3

无需使用regex to remove []

<强>代码：

import ast
with open("check.txt") as inp:
    for line in inp:
        check=ast.literal_eval(line.strip().strip(","))        
        print " ".join(check)

<强>输出：

abc 123 apple red <a href='link1'</a>
abc 124 orange blue <a href='link2'</a>
abc 125 almond black <a href='link3'</a>
abc 126 mango pink <a href='link4'</a>

但是为了得到href的值，我使用了regex

<强>代码1：

import re
import ast
with open("check.txt") as inp:
    for line in inp:
        check=ast.literal_eval(line.strip().strip(",")) 
        if re.search("'([^']*?)'",check[4]):
            check[4]=re.search("'([^']*?)'",check[4]).group(1)
        print " ".join(check)

<强>输出：

abc 123 apple red link1
abc 124 orange blue link2
abc 125 almond black link3
abc 126 mango pink link4

根据您的要求

 a="<a href='link1'>zzz</a>"
 print re.search("'([^<]*?)<",a).group(1)

<强>输出：

link1'>zzz

<强>代码2：

import re
import ast
with open("check.txt") as inp:
    for line in inp:
        check=ast.literal_eval(line.strip().strip(",")) 
        if re.search("'([^<]*?)<",a):
            check[4]=re.search("'([^<]*?)<",a).group(1)
        print " ".join(check)

Answer 4

由于您的数据是有效的python数据结构，因此您可以使用ast.literal_eval：

来阅读它

>>> import ast
>>> ast.literal_eval('''["abc","123","apple","red","<a href='link1'</a>"]''')
['abc', '123', 'apple', 'red', "<a href='link1'</a>"]

你也可以通过取第9个字符之后的所有字符直到第5个字符到最后一个来剪切字符串中的链接：

>>> s = "<a href='link1'</a>"
>>> s[9:-5]
'link1'

把它放在一起：

with open(outfile, 'w') as output:
    with open(filename) as lines:
        for line in lines:
            values = ast.literal_eval(line)
            values[4] = values[4][9:-5]
            output.write(' '.join(values))

Answer 5

每行可按如下方式处理：

>>>line = ["abc","123","apple","red","<a href='link1'>zzz</a>"]

>>>' '.join([k if 'href=' not in k else k[9:-4] for k in line])
"abc 123 apple red link1'>zzz"

Answer 6

在文件的内容周围添加括号，您有一个有效的JSON对象：

import json
with open(filename) as lines:
    output = json.loads("[" + lines.read() + "]")

现在您可以处理这些行，例如删除链接周围的锚点：

import re
for line in output:
    line[4] = re.search(r"'([^']*)'", line[4]).group(1)
    print " ".join(line)

Answer 7

这段代码怎么样？

from __future__ import print_function, unicode_literals
import ast
import io
import re
import traceback

input_str = """["abc","123","apple","red","<a href='link1'</a>"],

["abc","124","orange","blue","<a href='link2'</a>"],

["abc","125","almond","black","<a href='link3'</a>"],

["abc","126","mango","pink","<a href='link4'</a>"]"""

filelikeobj = io.StringIO(input_str)

for line in filelikeobj:
    line = line.strip().rstrip(",")
    if line:
        try:
            line_list = ast.literal_eval(line)
        except SyntaxError:
            traceback.print_exc()
            continue
        for li in line_list[:-1]:
            print(li, end=" ")

        s = re.search("href\s*=\s*['\"](.*)['\"]", line_list[-1], re.I)
        if s:
            print(s.group(1), end="")
        print()

在python中格式化文本文件

7 个答案: