如何使用jq查找JSON对象中的值与给定条件匹配的所有路径?

时间:2015-09-09 03:41:57

标签: json jq

有没有办法可以使用jq查找包含与给定条件匹配的值的所有路径?

例如,给定以下JSON,我想返回“age”的值> 35的所有路径,而不管包含该字段的结构的深度如何:

{  
  "springfield":{  
    "marge":{  
      "age":30
    },
    "homer":{  
      "age":40,
      "job":"xyz"
    }
  },
  "shelbyville":{  
    "zone1":{  
      "john":{  
        "age":10
      }
    },
    "zone2":{  
      "mark":{  
        "age":50
      }
    }
  },
  "homeless1":{  
    "age":25
  },
  "homeless2":{  
    "age":60
  }
}

因此执行会产生类似:

[
  ["springfield", "homer"],
  ["shelbyville", "zone2", "mark"],
  ["homeless2"]
]

1 个答案:

答案 0 :(得分:2)

以下测试使用jq 1.4和jq 1.5:

$ jq -M -c '(paths | select(.[length-1] =="age")) as $path
    | if (getpath($path) > 35) then $path else empty end' ages.json
["springfield","homer","age"]
["shelbyville","zone2","mark","age"]
["homeless2","age"]

以下要求jq 1.5:

$ jq -c --stream 'select(length == 2 and .[0][-1] == "age" 
    and .[1] > 35)' ages.json
[["springfield","homer","age"],40]
[["shelbyville","zone2","mark","age"],50]
[["homeless2","age"],60]

这些都可以很容易地适应产生类似的输出。