Question

所以我有一个计时器，每次运行时都会更改图片框中的图像。我生成了一个随机数，取决于它将停在该图像上的数字。所以最初计时器第一次运行时没有失败，它会在没有问题的情况下停在正确的图像上。它第二次通过它会出现故障并且出错，第三次它会在1秒左右停止并且第四次冻结。我不明白的是，定时器如何在第一次完美工作并停止（我认为会重置定时器）然后第二次按下按钮再次激活定时器并且它搞砸了？。

这是我的一些代码：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Timers;
using System.Windows.Forms;

namespace WheelOfFortune
{
public partial class f : Form
{
    private static Random r = new Random();
    private static int spin = 0;
    private static int t1 = 0;
    private static int t2 = 0;
    private static int t3 = 0;
    private static int rn = 0;
    private static System.Timers.Timer st = new System.Timers.Timer();

    public f()
    {
        InitializeComponent();

    }

    private void Wheel_Click(object sender, EventArgs e)
    {

    }

    private void Spin_Click(object sender, EventArgs e)
    {          
        if (spin == 0) {
            t1 = 0;
            t2 = 0;
            t3 = 0;
            spin = 1;
            rn = r.Next(1, 53);
            Console.WriteLine("" + rn);
            st.Stop();
            st.Elapsed += new ElapsedEventHandler(OnTimedEvent);
            st.Interval = 15;
            st.Start();
        }

    }

    private static void OnTimedEvent(object source, ElapsedEventArgs e)
    {
        t1 = t1 + 6;
        if (t1 == 1)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0001;
        }
        else if (t1 == 2)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0002;
        }
        else if (t1 == 3)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0003;
        }
        else if (t1 == 4)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0004;
        }
        else if (t1 == 5)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0005;
        }
        else if (t1 == 6)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0006;
        }
        else if (t1 == 7)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0007;
        }
        else if (t1 == 8)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0008;
        }
        else if (t1 == 9)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0009;
        }
        else if (t1 == 10)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0010;
        }
        else if (t1 == 11)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0011;
        }
        else if (t1 == 12)
        {
            Wheel.Image = Properties.Resources.Wheel_Test_0012;

            if(rn == 2)
            {
                t2 = t2 + 1;
                if (t2 == 1)
                {
                    t3 = t3 + 1;
                    if (t3 == 4)
                    {
                        spin = 0;
                        t3 = 0;
                        t1 = 0;

                        st.Stop();
                    }
                    t2 = 0;
                }

            }
        }

此后代码反复重复，因为有624个图像要经过，因为在开始时一次跳过6个然后将逐渐减慢。（我还没有实现减速部分。）

我似乎无法看到为什么计时器不会重置并再次执行相同操作的原因，我错过了什么？

Answer 1

您是否知道可以使用资源管理器来减少代码。

ResourceManager _resourceManager= Resources.ResourceManager;
...

计时器事件

 string _imageName=SomeLeftPaddFunction(4,"0",t1);//function to always pad to 4 0's
 Wheel.Image = (Bitmap)_resourceManager.GetObject("Wheel_Test_"+_imageName);

缓存图片

public class ImageCacheItem
{
    int Index{get;set;}
    Bitmap Image{get;set;}
} 
...
List<ImageCacheItem> _imageCache=new List<ImageCacheItem>();
....

计时器事件

Wheel.Image=_imageCache.Where(p=>p.Index==t1).FirstOrDefault();
if(Wheel.Image==null)
{ 
    string _imageName=SomeLeftPaddFunction(4,"0",t1);//function to always pad to 4 0's
    _imageCache.Add(new {Index=t1,Image=(Bitmap)_resourceManager.GetObject("Wheel_Test_"+_imageName);
    Wheel.Image=_imageCache.Where(p=>p.Index==t1).First();

}

C＃中计时器的问题

1 个答案: