Question

我正在尝试在Python的新线程中从dll创建一个COM对象 - 所以我可以在该线程中运行消息泵：

from comtypes.client import CreateObject
import threading

class MessageThread(threading.Thread):

    def __init__(self):
        threading.Thread.__init__(self)
        self.daemon = True

    def run(self):
        print "Thread starting"
        connection = CreateObject("IDMessaging.IDMMFileConnection")
        print "connection created"

a = CreateObject("IDMessaging.IDMMFileConnection")
print "aConnection created"
t = MessageThread()
t.start()

这是我得到的错误跟踪：

aConnection created
Thread starting
>>> Exception in thread Thread-1:
Traceback (most recent call last):
  File "c:\python26\lib\threading.py", line 532, in __bootstrap_inner
    self.run()
  File "fred.py", line 99, in run
    self.connection = CreateObject("IDMessaging.IDMMFileConnection")
  File "c:\python26\lib\site-packages\comtypes\client\__init__.py", line 235, in CreateObject
    obj = comtypes.CoCreateInstance(clsid, clsctx=clsctx, interface=interface)
  File "c:\python26\lib\site-packages\comtypes\__init__.py", line 1145, in CoCreateInstance
    _ole32.CoCreateInstance(byref(clsid), punkouter, clsctx, byref(iid), byref(p))
  File "_ctypes/callproc.c", line 925, in GetResult
WindowsError: [Error -2147221008] CoInitialize has not been called

有什么想法吗？

Answer 1

您需要在线程上调用CoInitialize()（或CoInitializeEx()），然后才能在该线程上创建COM对象。

from win32com.client.pythoncom import CoInitialize
CoInitialize()

Answer 2

据我记得（很久以前我用COM组件编写了很多代码）如果你的COM对象使用STA，你必须在每个线程~~上调用CoInitialize。~~

http://msdn.microsoft.com/en-us/library/ms678543(VS.85).aspx

但我不知道如何在python中调用该函数。

这是MSDN Doc

http://msdn.microsoft.com/en-us/library/ms678543(VS.85).aspx

Answer 3

使用PyCharm和Python 2.7更新目前的经验：您需要导入：

countDown;
counter = 60;

constructor() {
        this.countDown = Observable.timer(0,1000)
            .take(this.counter)
            .map(() => --this.counter);
}

然后运行线程：

from pythoncom import CoInitializeEx
from pythoncom import CoUninitialize

PyCharm与STA公寓混淆，你需要启用真正的多线程。

每个def run(self): res = CoInitializeEx(0) #<your code> CoUninitialize()都必须以CoInitialize()终止，因此请确保您的代码在出现错误时遵循此规则。

为什么我不能在Python的新线程中创建COM对象？

3 个答案: