这是基于Todilo先前的question。
以下接受的答案很有效,除了我需要返回除了每种类型的最新类型之外的所有类型为null的记录:
var query = Posts.GroupBy(p => p.Type)
.Select(g => g.OrderByDescending(p => p.Date)
.FirstOrDefault()
)
方案如下:
+----+--------------------------+-------+------------+
| id | content | type | date |
+----+--------------------------+-------+------------+
| 0 | Some text | TypeA | 2013-04-01 |
| 1 | Some older text | TypeA | 2012-03-01 |
| 2 | Some even older texttext | TypeA | 2011-01-01 |
| 3 | Sample | | 2013-02-24 |
| 4 | A dog | TypeB | 2013-04-01 |
| 5 | And older dog | TypeB | 2012-03-01 |
| 6 | An even older dog | TypeB | 2011-01-01 |
| 7 | Another sample | | 2014-03-06 |
| 8 | Test | | 2015-11-08 |
+----+--------------------------+-------+------------+
结果应为
Some text | TypeA
Sample |
A dog | TypeB
Another sample |
Test |
答案 0 :(得分:2)
那是怎么回事:
var query = Posts
.GroupBy(p => p.Type)
.Select(g => g.OrderByDescending(p => p.Date).FirstOrDefault()).ToList()
var lostNullItems = Posts.Where(p => p.Type == null && !query.Contains(p));
var newQuery = query.Union(lostNullItems);
如果您不需要您可以使用的物品的订单:
var query = Posts
.GroupBy(p => p.Type)
.SelectMany(g =>
{
var result = g.OrderByDescending(p => p.Date);
return g.Key == null ? result ? Enumerable.Repeat(result.First(), 1);
});
此代码未经过测试。
答案 1 :(得分:1)
请尝试以下代码。由于分组,订单不一样
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
DataTable dt = new DataTable();
dt.Columns.Add("id", typeof(int));
dt.Columns.Add("content", typeof(string));
dt.Columns.Add("type", typeof(string));
dt.Columns["type"].AllowDBNull = true;
dt.Columns.Add("date", typeof(DateTime));
dt.Rows.Add(new object[] { 0, "Some text", "TypeA", DateTime.Parse("2013-04-01")});
dt.Rows.Add(new object[] { 1, "Some older text", "TypeA", DateTime.Parse("2012-03-01")});
dt.Rows.Add(new object[] { 2, "Some older texttext", "TypeA", DateTime.Parse("2011-01-01")});
dt.Rows.Add(new object[] { 3, "Sample", null, DateTime.Parse("2013-02-24")});
dt.Rows.Add(new object[] { 3, "A dog", "TypeB", DateTime.Parse("2013-04-01")});
dt.Rows.Add(new object[] { 4, "And older dog", "TypeB", DateTime.Parse("2012-03-01")});
dt.Rows.Add(new object[] { 5, "An even older dog", "TypeB", DateTime.Parse("2011-01-01")});
dt.Rows.Add(new object[] { 4, "Another sample", null, DateTime.Parse("2014-03-06")});
dt.Rows.Add(new object[] { 5, "Test", null, DateTime.Parse("2015-11-08")});
var results = dt.AsEnumerable()
.GroupBy(x => x.Field<string>("type"))
.Select(x => x.Key == null ? x.ToList() : x.Select(y => new {date = y.Field<DateTime>("date"), row = y}).OrderByDescending(z => z.date).Select(a => a.row).Take(1))
.SelectMany(b => b).Select(c => new {
content = c.Field<string>("content"),
type = c.Field<string>("type")
}).ToList();
}
}
}