我有一个ID列表:
(1, 2, 3, 6, 7)
还有一张桌子:
id | anothercolumn
------------------
1 | NULL
2 | foo
4 | bar
5 | NULL
6 | NULL
我想从列表中检索不是我的表的ID的值。
预期结果:
3, 7
我试过这样的事情:
SELECT i
WHERE i IN (1, 2, 3, 6, 7)
AND i NOT IN (SELECT id FROM mytable);
但这不是一个有效的MySQL查询(需要FROM
)。
还有这种可能性:
SELECT i
FROM (
SELECT 1 AS i
UNION SELECT 2
UNION SELECT 3
UNION SELECT 6
UNION SELECT 7 ) AS mylistofids
LEFT JOIN mytable
ON mytable.id = i
WHERE mytable.id IS NULL;
这样可行,但如果我的ID列表变大,查询很快就会很大......
我还可以为我的id列表创建一个临时表:
CREATE TEMPORARY TABLE mylistofids (
i INT
);
INSERT INTO mylistofids (i) VALUES (1), (2), (3), (6), (7);
然后在LEFT JOIN
:
SELECT i
FROM mylistofids
LEFT JOIN mytable
ON mytable.id = i
WHERE mytable.id IS NULL;
这也有效,但在我的情况下,我没有权利创建一个表(临时或非临时)。
您是否看到了以最好的方式解决此问题的方法?
答案 0 :(得分:6)
临时表是最好的解决方案,但如果不可能,那么你可以通过选择常量并将它们合并在一起来捏造临时表。
使用此解决方案,您可以执行以下操作: -
SELECT i
FROM
(
SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 6 UNION SELECT 7
) AS mylistofids
LEFT JOIN mytable
ON mytable.id = i
WHERE mytable.id IS NULL;
您还可以通过交叉连接数字范围生成大量数字(假设您正在处理整数ID)。然后选择IN子句中的那些: -
SELECT i
FROM
(
SELECT units.i + tens.i * 10 + hundreds.i * 100 + thousands.i * 1000 + tensthousands.i * 10000 AS i
FROM (SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0 ) AS units
CROSS JOIN (SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0 ) AS tens
CROSS JOIN (SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0 ) AS hundreds
CROSS JOIN (SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0 ) AS thousands
CROSS JOIN (SELECT 1 AS i UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0 ) AS tensthousands
) AS mylistofids
LEFT JOIN mytable
ON mytable.id = i
WHERE mylistofids.i IN (1, 2, 3, 6, 7)
AND mytable.id IS NULL;