我有一个postgres函数，输入参数是json。我需要从这个JSON中提取值并将其插入到不同的表中。
管理员将从前端创建表单，部分，步骤和问题，这些数据将作为JSON获取，我需要相应地将数据插入表中。这里每个表单可以有n个部分，ecah部分可以有n个步骤，每个步骤有n个这样的问题。我的想法是将值从JSON提取到变量中，并使用此变量插入表中。我对postgres很新，所以不要知道这是不是一个好主意。
请找到我将要获得的JSOn
{
"functionId":"",
"subFunctionId":"",
"groupId":"Audit",
"formId":"",
"formName":"sample form",
"submittedBy":"2000269",
"createdDate":"2015-08-06",
"updatedBy":"",
"updatedDate":"",
"comments":"",
"formStatusId":"",
"formStatus":"",
"formLanguage":"",
"isFormConfigured":"",
"formChange":"Yes",
"sectionLevelChange":"Yes",
"isActive":"",
"formVersionNo":"",
"formFooterDetails":"",
"formHeaderDetails":"",
"images":[
{
"imageId":"",
"imageTempId":"",
"imageTempUrl":"",
"imageName":"",
"imageUrl":"",
"isDeleted":"",
"imagesDesc":""
}
],
"imagesDescLevel":"",
"sectionElements":[
{
"sectionElement":[
{
"sectionId":"",
"sectionTempId":"sectionId+DDMMHHSSSS",
"sectionName":"section1",
"sectionChange":"Yes",
"stepLevelChange":"Yes",
"sectionLabel":"",
"sectionOrder":"",
"outOfScopeSection":"false",
"punchListSection":"false",
"images":[
{
"imageId":"",
"imageTempId":"",
"imageTempUrl":"",
"imageName":"",
"imageUrl":"",
"isDeleted":"",
"imagesDesc":""
}
],
"imagesDescLevel":"",
"isDeleted":"",
"stepElements":[
{
"stepElement":[
{
"stepId":"",
"stepTempId":"stepId+DDMMHHSSSS",
"stepName":"step1",
"stepLabel":"",
"stepOrder":"",
"stepChange":"Yes",
"questionLevelChange":"Yes",
"images":[
{
"imageId":"",
"imageTempId":"",
"imageTempUrl":"",
"imageName":"",
"imageUrl":"",
"isDeleted":"",
"imagesDesc":""
}
],
"imagesDescLevel":"",
"isDeleted":"",
"questionAnswerElements":[
{
"questionAnswerElement":[
{
"questionId":"",
"questionClientUid":"",
"questionDescription":"",
"questionAccessibility":"",
"isPunchListQuestion":"",
"questionChange":"Yes",
"questionOrder":"",
"isDeleted":"",
"images":[
{
"imageId":"",
"imageTempId":"",
"imageTempUrl":"",
"imageName":"",
"imageUrl":"",
"isDeleted":"",
"imagesDesc":""
}
],
"imagesDescLevel":"",
"answerId":"",
"answerClientUid":"",
"elements":[
{
"element":[
{
"elementId":"",
"elementMapId":"",
"clientUid":"",
"clientClass":"",
"imageTempId":"",
"imageTempUrl":"",
"elementType":"Question",
"elementOrder":"",
"elementArributuesProp":[
{
"attributeId":"",
"attributeName":"",
"defaultValue":""
}
],
"elementArributuesVal":[
{
"value1":"item1"
}
],
"rule":[
{
"ruleId":"1",
"ruleName":"Mandatory",
"formula":"i>a",
"formulaData":"i>50",
"isDeleted":"",
"addAction":[
{
"actionId":"1",
"actionDescription":"",
"actionTag":"",
"actionOutput":"",
"actionOutputValue":"",
"numberOfFields":"",
"isDeleted":""
}
]
}
]
}
]
}
]
}
]
}
]
}
]
}
]
}
]
}
]
}
如何从JSON中将值提取到变量中。任何帮助都是明确指出的
由于
答案 0 :(得分：0)
我可以通过以下查询获取详细信息
select
line_item4->'questionDescription',line_item6->'elementMapId',line_item7->'attributeId',line_item8->'value1',line_item9->'ruleId',line_item10->'actionId'
from tbl d,
json_array_elements(d.j->'sectionElements') l,
json_array_elements(l->'sectionElement') AS line_item,
json_array_elements(line_item->'stepElements') AS line_item1,
json_array_elements(line_item1->'stepElement') AS line_item2,
json_array_elements(line_item2->'questionAnswerElements') AS line_item3,
json_array_elements(line_item3->'questionAnswerElement') AS line_item4,
json_array_elements(line_item4->'elements') AS line_item5,
json_array_elements(line_item5->'element') AS line_item6,
json_array_elements(line_item6->'elementArributuesProp') AS line_item7,
json_array_elements(line_item6->'elementArributuesVal') AS line_item8,
json_array_elements(line_item6->'rule') AS line_item9,
json_array_elements(line_item9->'addAction') AS line_item10
由于
答案 1 :(得分：0)
您可以使用Postgres函数获取值，但是您应该知道如何使用它们-例如，下面，我根据表的特定ID从上下文列中获取了值-
select id,context,(SELECT *
FROM json_array_elements((tr.context#>'{path}')::json) as obj
WHERE obj->>'type' = 'Hospital' )->>'displayName' as each_attribute from task_results tr where tr.id = '11e99de6-f2c6-66e8-b45f-1ff041905861'
上下文列中有此数据-
{
"use": "",
"path": [
{
"id": "11e837f8-42f2-1c62-8cb2-f703eb1e89ad",
"type": "Root",
"displayName": "Virtual Hospital"
},
{
"id": "11e837fb-7c5e-57e2-91ac-ab2e1b35a7e9",
"type": "Hospital",
"displayName": "Test hospital"
},
{
"id": "11e8d3c4-e68a-0868-b88f-07054484efea",
"type": "Room",
"displayName": "vivek's room"
}
],
"compoundId": "05a34eccd38956e6b7dc1ba85e5c04c29ef3b9cd5f15a73e448222780d4671c86"
}
因此从上面的json中，我只需要存储在displayName中的医院名称，而“类型”应仅是医院。 在上面的帮助下。