Question

假设我有以下两个字符串："Hey there"和"there is a ball"

我希望输出为True，因为第一个以"there"结尾，第二个以"there"开头。

另外，如果我知道重叠的长度会很有帮助。

Answer 1

这应该有效：

def endOverlap(a, b):
    for i in range(0, len(a)):
        if b.startswith(a[-i:]):
            return i
    return 0

a = "Hey there"
b = "there is a ball"
c = "here is a ball"
d = "not here is a ball"

print(a, b, endOverlap(a, b))
print(a, c, endOverlap(a, c))
print(a, d, endOverlap(a, d))

编辑：修改后返回重叠长度，并且如果预期只有字符串的一小部分重叠，则效率更高。然后修正了一个错误。

Answer 2

# do your str checks here...
if (str1.split()[-1] == str2.split()[0]):

Answer 3

要知道两个字符串的重叠，请使用生成器和endswith字符串方法。此子字符串的max值将是最大重叠：

>>> str1 = "Hey there"
>>> str2 = "there is a ball"
>>> overlap = max((str2[:x] for x in range(1,len(str2) + 1) if str1.endswith(str2[:x])),key = len)
>>> overlap
'there'

要返回True使用if语句或bool类型：

>>> if overlap:
...     print True
... 
True
>>> bool(overlap)
True

要知道长度，只需使用len函数：

>>> len(overlap)
5

检查字符串是否以另一个字符串

3 个答案: