无法从浏览器打开Android应用程序

时间:2015-09-08 11:20:09

标签: android android-browser

我已经看到很多从浏览器打开应用程序的解决方案,但不知道我做错了什么。实际上我需要通过链接打开我的应用程序(如果在用户设备上可用)。用户将通过短信获取链接,当他点击该链接时,我的java脚本代码将在用户设备中查找该特定应用程序(通过方案)。下面的代码在IOS中完美运行,但在android中没有。请帮忙。

我尝试从浏览器打开应用的网页链接代码:

        var appStoreURL =" https://itunes.apple.com/us/app/workout-trainer/id395686735?mt=8&#34 ;;

    //Check is device is iOS
    var iOS = (navigator.userAgent.match(/(iPad|iPhone|iPod)/g) ? true : false);
    var appiOSUrlScheme = "myappscheme://" + window.location.search;

   //alert(appUrlScheme);

    var weblink="https://example/Home.net"

    var AndroidStoreURL = "https://itunes.apple.com/us/app/workout-trainer/id395686735?mt=8";

    var ua = navigator.userAgent.toLowerCase();
    var isAndroid = ua.indexOf("android") > -1; //&& ua.indexOf("mobile");
    var appAndroidUrlScheme = " myappscheme://" + window.location.search; ;


    if (iOS) {
        //If the app is not installed the script will wait for 2sec and redirect to web.
        alert(appiOSUrlScheme);
        var loadedAt = +new Date;
        setTimeout(
               function () {
                   if (+new Date - loadedAt < 2000) {
                       window.location = appStoreURL;
                   }
               }
               , 25);
        //Try launching the app using URL schemes
        window.open(appiOSUrlScheme, "_self");
    }
    else if (isAndroid) {
        alert(appAndroidUrlScheme);
        //If the app is not installed the script will wait for 2sec and redirect to web.
        var loadedAt = +new Date;
        setTimeout(
               function () {
                   if (+new Date - loadedAt < 2000) {
                       window.location = AndroidStoreURL;
                   }
               }
               , 25);
        //Try launching the app using URL schemes
               window.open(appAndroidUrlScheme, "_self");
    }
    else {
        //Launch the website
        window.location = weblink;
    }

</script>

Android Mainfest代码:

 <intent-filter>
            <action
                android:name="android.intent.action.VIEW" />
            <category
                android:name="android.intent.category.DEFAULT" />
            <category
                android:name="android.intent.category.BROWSABLE" />
            <category android:name="android.intent.category.VIEW" />

            <data
        android:pathPrefix="/Home"
        android:scheme="myappscheme" />
        </intent-filter>

0 个答案:

没有答案