Swift：带参数的NSURL无效

Question

这是我与UIActivityVieController共享Google地图链接的代码：

 if let myWebsite = NSURL(string: "http://maps.google.com/?q=<\(myLatitude)>,<\(myLongitude)>") {
        let objectsToShare = [alertMessage, myWebsite]
        let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: nil)
        //New Excluded Activities Code
        activityVC.excludedActivityTypes = [UIActivityTypeAirDrop, UIActivityTypeAddToReadingList]
        self.presentViewController(activityVC, animated: true, completion: nil)
    }

此链接无效;不调用if语句。我该如何解决这个问题？

Answer 1

您的NSURL的格式应如下所示：

let myWebsite = NSURL(string: "http://maps.google.com/?q=\(myLatitude),\(myLongitude)")

要在字符串中使用字符串，您应该编写

"My string \(otherString)";