我在将模式div中的表格中的数据插入表格元素时遇到问题,我想根据复选框选中的数据显示内容,当我点击"添加"按钮。
这是我的代码:
模态的表格代码:
<div class="row">
<div class="modal fade" id="mod_search" role="dialog">
<div class="modal-dialog modal-lg">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Members</h4>
</div>
<div class="modal-body">
<table class="table table-hover table-managed">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
<th>Speciality</th>
</tr>
</thead>
<tbody>
<?php
$sql_search = "SELECT * FROM `personal_profile`";
$sql_run = mysql_query($sql_search);
while($m = mysql_fetch_array($sql_run))
{
?>
<tr>
<td><input type="checkbox" name="member_select[]"></td>
<td><?php echo @$m['lastname'].', '.@$m['firstname'].' '.@$m['middlename'];?></td>
<td><?php echo @$m['speciality'];?></td>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success" name="add_button" id="button_add">Add</button>
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
</div>
所选数据代码表:
<div class="row">
<div class="form-group">
<div class="col-md-8 col-md-offset-2">
<table class="table table-managed table-hover">
<thead>
<tr>
<th>No.</th>
<th>Name</th>
<th>Speciality</th>
</tr>
</thead>
<tbody>
<tr>
<?php
$sql_select="SELECT * FROM `event_attendees` WHERE `id`='".@$_REQUEST['member_select']."'";
$sql_run=mysql_query($sql_select);
while($row=mysql_fetch_array($sql_run))
{
}
?>
<td></td>
<td id="name_row"></td>
<td id="speciality_row"></td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
希望你能帮助我。我一直在互联网上看,但没有什么与我的问题完全相关。
以下是图片:
第一张图片是您点击&#34;搜索&#34;时显示的模式。如果&#34;会员&#34;从原始页面(第2张图像)中选择单选按钮。
答案 0 :(得分:0)
如果我已经理解你正在尝试做什么,在你点击'添加'时调用的页面中 - 我认为这是原始页面,图像2 - 在显示页面之前你需要在你的php中使用以下内容:
if(isset($_POST['member_select']){
$items=$_POST['member_select'];
foreach($items AS $id){
/* do the following with your chosen SQL DB approach
(I would recommend looking at PDO):*/
INSERT INTO `event_attendees` (name, specialism)
SELECT name, specialism FROM `personal_profile` WHERE `id`= $id
}
}
错误检查等。
稍微有效的替代方案是:
if(isset($_POST['member_select']){
$items=$_POST['member_select'];
$list='';
foreach($items AS $id) $list.=$id.',';
rtrim($list,',');
/* do the following with your chosen SQL DB approach
(I would recommend looking at PDO):*/
INSERT INTO `event_attendees` (name, specialism)
SELECT name, specialism FROM `personal_profile` WHERE `id` IN ($list)
}
答案 1 :(得分:0)
这就是我得到它的方式。 :)
//set the function
$("#add_button").click(function(){
/* check for your table where to send the data from the current table then
use the selector for the checkboxes when clicked */
$('#table_select input[type="checkbox"]:checked').each(function(){
var getRow = $(this).parents('tr'); //variable for the entire row
var value = (getRow.find('td:eq(2)').html()); //data for names
var value1 = (getRow.find('td:eq(3)').html()); //data for specialty
var value3 = (getRow.find('td:eq(1)').html()); //data for prc
$('#attendee_table tr:last').append('<tr><td></td><td><input type="text" class="form-control" name="prc[' + attendees_id + ']" id="prc" value="' + value3 + '" readonly></td><td><input type="text" class="form-control" value="' + value + '" id="names" name="name[' + attendees_id + ']" readonly></td><td><input type="text" class="form-control" value="' + value1 + '" id="specialties" name="specialty[' + attendees_id + ']" readonly></td><td><input type="button" class="btn btn-warning" name="delete_btn1[' + attendees_id + ']" id="delete_btn1" data-id="' + attendees_id + '" onclick="deleteMem(this)" value="Delete"></td></tr>');
/* then append your row (include the variables to the value of the textboxes.
I use textboxes for it may able to save the data in the database later. :) */
$("#mod_search").modal('hide');
});
});