我有一张桌子＆＃39; operation_record＆＃39;像这样：
日期操作
1-1 a
1-1 b
1-1 b
1-1 a
1-1 a
1-1 c
1-1 a
1-2 c
1-2 b
1-2 c
1-2 a
1-2 a
1-2 b
1-2 c
我想要的是这样的：
data operation_a operation_b operation_c
1-1 4 2 1
1-2 2 2 3
如果操作是固定的，我可以使用这样的东西：
select o.uc, ,a.rc operaiton_a, b.rc operaiton_b, c.rc operaiton_c from
(select date uc,count(1) rc from operaion_record group by date) o
left join
(select date uc,count(1) rc from operaion_record where operation='a' group by date)a on o.uc=a.uc
left join
(select date uc,count(1) rc from operaion_record where operation='b' group by date)b on o.uc=b.uc
left join
(select date uc,count(1) rc from operaion_record where operation='c' group by date)b on o.uc=c.uc
但问题是，操作可能会有所不同。
但是，我可以通过
获得这些操作select distinct(operation) from operation_record
然后，我如何将这些值作为新列并获得这些计数？