在我的应用程序中,可以选择从列表视图中选择不同的项目。所选项目将存储到一个数组中,后台将设置为listview中的选定项目。哪个工作正常。问题是我想要取消选择项目,如果我以前选择它。也想要从所选项目的数组中删除它。我正在寻找它几个小时。请帮助我。谢谢你提前。
list = (ListView) findViewById(R.id.list);
// list.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);
adapter=new LocationListAdapter(mActivity, locationList);
list.setAdapter(adapter);
selectedlocations = new String[locationList.size()];
list.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
// TODO Auto-generated method stub
if (selected != null) {
// selected.setBackgroundResource(R.drawable.list_item_bg_pressed);
}
selected = view;
selected.setBackgroundResource(R.drawable.list_item_bg_pressed);
selecteditem = position;
selectedlocations[position] = locationList.get(selecteditem)
.getId();
((LocationListAdapter)list.getAdapter()).toggleSelected(new Integer(position));
System.out.println("Selected position:" + selecteditem + ","
+ selectedlocations[position]);
}
});
答案 0 :(得分:0)
你试过这个吗?
myListView.clearChoices();
myAdapter.notifyDataSetChanged();
这将清除您所做的所有选择。
答案 1 :(得分:0)
myListView.clearChoices();
myListView.requestLayout();
答案 2 :(得分:0)
使用一个列表来存储选定的对象。如果它已经存在,那么删除它。还有一件事你不能从数组中删除元素,所以使用List。
list = (ListView) findViewById(R.id.list);
selectedlocations = new ArrayList<String>();
list.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
// TODO Auto-generated method stub
if (selected != null) {
// selected.setBackgroundResource(R.drawable.list_item_bg_pressed);
}
selected = view;
selected.setBackgroundResource(R.drawable.list_item_bg_pressed);
selecteditem = position;
String item = ""+locationList.get(selecteditem).getId();
if(selectedlocations.contains(item)){
selectedlocations.remove(item);
}else{
selectedlocations.add(item);
}
((LocationListAdapter)list.getAdapter()).toggleSelected(new Integer(position));
System.out.println("Selected position:" + selecteditem + ","
+ selectedlocations[position]);
}
});