Question

我有一个选择框，它应该通过选项更改来更新我的SQL数据库。因为在这种情况下我没有正常的提交输入字段，if(isset($_GET['submit']))不起作用，但我不知道如何以正确的方式编写语句：

<?php
if(isset($_GET['submit'])){
    $status = $_GET['status'];
    $id = $_GET['id'];
        $pdo = Database::connect();
        $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $sql = "UPDATE colors set status = ? WHERE id = '$id'";
        $q = $pdo->prepare($sql);
        $q->execute(array($status));
        Database::disconnect();
}
?>      

                    <form action="index.php" method="get">
                        <select name="status" onchange='this.form.submit()'>
                        <option value="red">red</option>
                        <option value="blue">blue</option>
                    </select>
<?php echo "<input id='id' type='hidden' value='"$id"'>";?>
</form>

Answer 1

尝试替换此行

if(isset($_GET['submit'])){

带

if(array_key_exists('status',$_GET) && $_GET['status']!=""){

Answer 2

可能就像

一样简单

if(!empty($_GET['status'])){
   ....
}

Answer 3

试试这个：

<?php
$id = "YourID";
if(!empty($_GET["status"])){
    $status = $_GET['status'];
    if(isset($_GET['id']) && $_GET['id'] != ""){
        $id = $_GET["id"];
        //continue...
    }else{
        //display error (ID has not been set.)
    }
}
?>

<form action="index.php" method="get">
    <select name="status" onchange='this.form.submit()'>
        <option value="red">red</option>
        <option value="blue">blue</option>
    </select>
    <?php echo "<input name='id' id='id' type='hidden' value='$id'>";?>
</form>

如何在selectbox选项更改（php）上更新我的SQL数据库？

3 个答案: