hasRole()不工作错误Http状态403 - 访问被拒绝

时间:2015-09-08 06:10:43

标签: java spring-security

以下是我的security-config文件中的配置:

<security:http use-expressions="true">
    <security:intercept-url pattern="/adminarea"
        access="hasRole('admin')" />
    <security:intercept-url pattern="/logincheck"
        access="permitAll" />
    <security:intercept-url pattern="/newaccount"
        access="permitAll" />
    <security:intercept-url pattern="/createnewaccount"
        access="permitAll" />
    <security:intercept-url pattern="/home"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/static/**"
        access="permitAll" />
    <security:intercept-url pattern="/" access="permitAll" />
    <security:intercept-url pattern="/**" access="denyAll" />
    <security:form-login login-page="/"
        authentication-failure-url="/?error=true" default-target-url="/home" />
</security:http>

我使用的是spring default login,工作正常。但是当我尝试/adminarea时,我收到Http Status 403 - Access is denied错误。任何帮助。

已编辑:AuthenticationManager

<security:authentication-manager>
    <security:authentication-provider>
        <security:jdbc-user-service
            data-source-ref="dataSource" />
    </security:authentication-provider>
</security:authentication-manager>
JSP上的

代码:

<sec:authentication property="principal"/>
<sec:authorize access="hasRole('admin')">
    <a href="${pageContext.request.contextPath}/adminarea">Admin Area</a>
</sec:authorize>

之后的第一个标记输出
  

rg.springframework.security.core.userdetails.User@6d8e08d5:用户名:zubi@yahoo.com;密码保护];启用:true; AccountNonExpired:true; credentialsNonExpired:true; AccountNonLocked:true;授权机构:admin

第二个标签不输出任何内容。

2 个答案:

答案 0 :(得分:0)

我假设您已创建以下表格

  create table users(
      username varchar_ignorecase(50) not null primary key,
      password varchar_ignorecase(50) not null,
      enabled boolean not null);

  create table authorities (
      username varchar_ignorecase(50) not null,
      authority varchar_ignorecase(50) not null,
      constraint fk_authorities_users foreign key(username) references users(username));
      create unique index ix_auth_username on authorities (username,authority);

应用程序上下文xml中的上述身份验证管理器配置需要哪些。

您已将角色admin插入authorities表。

答案 1 :(得分:0)

我通过将数据库中的角色设置为ROLE_XXX或我的ROLE_ADMIN来解决了问题。然后使用以下代码:

安全配置:

<security:intercept-url pattern="/adminarea"
        access="hasRole('ROLE_ADMIN')" />

JSP:

<sec:authorize access="hasRole('ROLE_ADMIN')">
    <a href="${pageContext.request.contextPath}/adminarea">Admin Area</a>
</sec:authorize>

从我的实验中得到它的工作。我想定义的角色需要在CAPITAL中,并且应该以{{1​​}}为前缀。

希望它有助于任何人遇到这个问题。