Question

我正在设计一个警报应用程序。

我正在使用一个充当我的闹钟的片段，想法是为每个新闹钟使用相同的片段（我不知道这是否正确）。

那么，我基本上试图添加，通过按下＆＃34;新警报＆＃34;按钮，同样的片段再次进入活动的布局，但当我按下按钮时，应用程序崩溃。有什么帮助吗？

我将片段插入到一个位于RelativeLayout内部的ScrollView内的LinearLayout

package com.example.roo.proyi;

import android.app.Fragment;

import android.support.v4.app.FragmentManager;
import android.support.v4.app.FragmentTransaction;
import android.support.v4.app.FragmentActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;

public class alarms extends FragmentActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_alarms);



        android.support.v4.app.FragmentManager fragmentManager = getSupportFragmentManager();
        final android.support.v4.app.FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
        alarm_fragment alarmFragment = new alarm_fragment();
        fragmentTransaction.add(R.id.alarmListContainer,alarmFragment);
        fragmentTransaction.commit();

        Button button_newAlarm = (Button)findViewById(R.id.button_new_alarm);
        button_newAlarm.setOnClickListener(
                new Button.OnClickListener() {
                    public void onClick(View v) {
                        alarm_fragment alarmFragment2 = new alarm_fragment();
                        fragmentTransaction.add(R.id.alarmListContainer,alarmFragment2);
                        fragmentTransaction.commit();
                    }

                    ;
                }
        );

.
.
.
.
.
.CONTINUES BUT IT IS IRRELEVANT
.
.
.

通过创建不同的碎片转移制作的最终解决方案

public class alarms extends FragmentActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_alarms);



        final android.support.v4.app.FragmentManager fragmentManager = getSupportFragmentManager();
        final android.support.v4.app.FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
        final alarm_fragment alarmFragment = new alarm_fragment();
        fragmentTransaction.add(R.id.alarmListContainer,alarmFragment);
        fragmentTransaction.commit();

        Button button_newAlarm = (Button)findViewById(R.id.button_new_alarm);
        button_newAlarm.setOnClickListener(
                new Button.OnClickListener() {
                    public void onClick(View v) {
                        android.support.v4.app.FragmentTransaction fragmentTransaction2 = fragmentManager.beginTransaction();
                        getSupportFragmentManager().beginTransaction();
                        alarm_fragment alarmFragment2 = new alarm_fragment();
                        fragmentTransaction2.add(R.id.alarmListContainer,alarmFragment2);
                        fragmentTransaction2.commit();
                    }

                    ;
                }
        );

Answer 1

您无法使用相同的FragmentTransaction在OnClickListener内添加片段。在交易中致电commit()后，您无法再次使用它。致电getSupportFragmentManager().beginTransaction()以获得新交易。

Answer 2

检查此代码 -
1。它会检查您是否已在堆栈中添加了对话框片段。如果是，它将删除片段并使用新的argument添加新片段，如果它不存在，它仍会添加片段。

看看你是否可以在代码中加入这种方法 -

    void showDialog() {
    mStackLevel++;

    // DialogFragment.show() will take care of adding the fragment
    // in a transaction.  We also want to remove any currently showing
    // dialog, so make our own transaction and take care of that here.
    FragmentTransaction ft = getFragmentManager().beginTransaction();
    Fragment prev = getFragmentManager().findFragmentByTag("dialog");
    if (prev != null) {
        ft.remove(prev);
    }
    ft.addToBackStack(null);

    // Create and show the dialog.
    DialogFragment newFragment = MyDialogFragment.newInstance(mStackLevel);
    newFragment.show(ft, "dialog");
}

Source is Android developer site

在运行时多次添加相同的片段

2 个答案: