我正在努力:
我需要用一个select语句来做这个,所以我尝试了尽可能多的我想象并搜索。我试过的最后一个就是这个:
SELECT a.ID,a.post_title,b.post_id,b.meta_value FROM ( SELECT DISTINCT ID FROM wp_posts UNION SELECT DISTINCT post_id FROM wp_postmeta ) x LEFT JOIN wp_posts a ON x.ID = a.ID LEFT JOIN wp_postmeta b ON x.post_id = b.post_id
但是,当我尝试时,它会告诉我:
#1054 - 'on clause'中的未知列'x.post_id'
我什么都没想到,有人会帮助我吗?
----编辑----
@Rahul,
这很好,但仍然返回非不同的值,我正在使用它,(注意,常见列:a.ID = yy.post_id):
SELECT a.ID, a.post_title, b.post_id, b.meta_value FROM wp_posts a LEFT JOIN ( SELECT DISTINCT ID FROM wp_posts )xx ON a.ID = xx.ID LEFT JOIN ( SELECT DISTINCT post_id FROM wp_postmeta )yy ON a.ID = yy.post_id LEFT JOIN wp_postmeta b ON b.post_id = yy.post_id WHERE a.post_type = 'product' AND a.post_status = 'publish' LIMIT 0 , 30
回归:
ID POST_TITLE POST_ID meta_value
141 Pastel de Teste 141 1
141 Pastel de Teste 141 1436921168:1
141 Pastel de Teste 141 123
141 Pastel de Teste 141可见