Question

大家好我在需要加载xml时遇到问题

我的代码就像

Stream.Seek(0, SeekOrigin.Begin);
xmlDoc.Load(Stream); //--> throw XmlException (multiple root elements in 14,22)
xmlDoc.PreserveWhitespace = true;

xml文件是

<soapenv:Envelope xmlns:dummy="

http://www.somedomian.com/dummybus/" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
    <soapenv:Header Id="IDH">
        <dummy:authentication>
            <id>Unique</id>
            <userid>myuser</userid>
        </dummy:authentication>
        <wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
            <wsu:Timestamp>
                <wsu:Created>2015-09-07T12:21:15</wsu:Created>
                <wsu:Expires>2015-09-08T12:21:15</wsu:Expires>
            </wsu:Timestamp>
        </wsse:Security>
    </soapenv:Header> <!--- This is line 14 and  > is a column 22--->
    <soapenv:Body>
        <dummy:dummybus>
            <msg>X1</msg>
        </dummy:dummybus>
    </soapenv:Body>
</soapenv:Envelope>

<Envelope>标记是文件的根，为什么发送此错误以及如何读取我的文件？

我找到了一些有趣的东西

当我保存文件时，不是将其保存在Stream中，而是完美加载

xmlDoc.Load(urlToFile);
xmlDoc.PreserveWhitespace = true;

似乎错误只发生在Stream中，为什么？

此方法将String中的xml转换为MemoryStream

public class XmlUtil
    {
        public static MemoryStream GenerateStreamFromString(string s)
        {
            MemoryStream stream = new MemoryStream();
            StreamWriter writer = new StreamWriter(stream);
            writer.Write(s);
            writer.Flush();
            stream.Position = 0;
            return stream;
        }

Answer 1

由于您是从流中读取的，因此我认为当您拨打xmlDoc.Load(Stream)时，它不会位于开头。你在电话会议前对流做了什么？

如果您的信息流支持搜索，您可以尝试在呼叫之前回到其开头：

Stream.Seek(0, SeekOrigin.Begin);
xmlDoc.Load(Stream);

XmlDocument.Load多个根元素

1 个答案: