我在mysql中有这个名为safespot的表
+---------+---------------+
| term_id | userid | safe |
+---------+--------|------+
| 1 | 1 | large number, unix timestamp here
| 1 | 2 | large number, unix timestamp here
| 1 | 3 | large number, unix timestamp here
| 1 | 4 | large number, unix timestamp here
+---------+--------+
这是表users
:
+----+-------------+-------------+
| id | userid | cash |
+----+-------------+-------------+
| 1 | 1 | 100000 |
| 2 | 2 | 100000 |
| 3 | 3 | 100000 |
+----+-------------+-------------+
我该怎么做
SELECT * FROM `users` where `userid`=1 and `cash`>= 1000 and " userid do not exist in table safespot" or "if the user exists in the safestop table, check if the current timestamp is higher than the safe colum)
所以基本上做一个查询,如果用户名不存在于safespot表中,也会返回它,或者如果确实存在,则该时间戳高于safe_value。
答案 0 :(得分:0)
SELECT * FROM `users` WHERE `userid`=1 AND `cash`>= 1000 AND (userid NOT IN (
SELECT DISTINCT userid FROM safespot
) OR (userid IN (
SELECT DISTINCT userid FROM safespot WHERE safe < UNIX_TIMESTAMP()
)
)
答案 1 :(得分:0)
使用WHERE NOT EXISTS
之类的
SELECT u.* FROM `users` u
where u.`userid`=1
and u.`cash` >= 1000
and ( NOT EXISTS ( select 1 from safespot where userid <> u.userid)
or EXISTS (select 1 from safestop where userid = u.userid and safe < CURRENT_TIMESTAMP));
答案 2 :(得分:0)
SELECT * FROM users u
LEFT JOIN safespot s ON s.userid = u.userid
WHERE
u.userid = 1
AND u.cash = 1000
AND (s.userid IS NULL OR s.safe > UNIX_TIMESTAMP())
这将返回用户
safespot
中没有条目,或safespot
中有一个条目,其值safe
大于当前时间戳。