Question

我想摆脱散列中每个属性中的value: <value>键值。并且像这样："total_interactions": 493.667 下面是不正确的格式，后面是我希望在json中实现的预期良好格式。

{
    "3": {
        "total_interactions": {
            "value": 493.667
        },
        "shares": {
            "value": 334
        },
        "comments": {
            "value": 0
        },
        "likes": {
            "value": 159.66666666666666
        },
        "total_documents": 6
    },
    "4": {
        "total_interactions": {
            "value": 701
        },
        "shares": {
            "value": 300
        },
        "comments": {
            "value": 0
        },
        "likes": {
            "value": 401
        },
        "total_documents": 1
    }
}

我希望它是这样的：

{
    "3": {
        "total_interactions": 493.6666666666667,
        "shares": 334,
        "comments": 0,
        "likes": 159.66666666666666,
        "total_documents": 6
    },
    "4": {
        "total_interactions": 701,
        "shares": 300,
        "comments": 0,
        "likes": 401,
        "total_documents": 1
    }
}

这是应该执行此操作但不起作用的代码。没有任何影响。不确定有什么问题

# the result_hash variable is the first hash with value: <value>
result_hash.each do |hash_item|
            hash_item.each do |key,value_hash|
                if( !value_hash.nil? )
                    value_hash.each do |k,v|
                        hash_item[key] = v
                    end
                end             
            end
        end

Answer 1

Max Williams的代码非常适合原地使用。您也可以在功能样式中执行此操作以获取新的，更正的哈希：

db_subset <- structure(list(created_utc = c(1430438400L, 1430438410L, 
1430438430L, 
1430438455L, 1430438470L, 1430438480L)), .Names = "created_utc", 
class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6"))

Answer 2

#t.__orderedIndex

之后：

hash = {"3"=>{"total_documents"=>6, "comments"=>{"value"=>0}, "total_interactions"=>{"value"=>493.667}, "shares"=>{"value"=>334}, "likes"=>{"value"=>159.666666666667}}, 
        "4"=>{"total_documents"=>1, "comments"=>{"value"=>0}, "total_interactions"=>{"value"=>701}, "shares"=>{"value"=>300}, "likes"=>{"value"=>401}}}

hash.each do |k,v| 
  v.each do |k2, v2|
    if v2.is_a?(Hash) && v2["value"]
      hash[k][k2] = v2["value"]
    end
  end
end

Answer 3

如果你不想改变你的初始哈希<div class="row"> <div class="columns large-12"> <ul class="small-block-grid-2 medium-block-grid-3 large-block-grid-4"> <li> <a href="http://127.0.0.1/makine/canon-powershot-elph-310-hs/" title="Canon PowerShot Elph 310 HS"> <img src="http://i.imgur.com/fwHd8zf.png" class="attachment-kucuk wp-post-image" alt="Canon_PowerShot_Elph_310_HS_428369_i0"> <h4>Canon PowerShot Elph 310 HS</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-powershot-s120/" title="Canon PowerShot S120"> <img src="http://i.imgur.com/HLuFBv0.png" class="attachment-kucuk wp-post-image" alt="Canon_PowerShot_S120_890378"> <h4>Canon PowerShot S120</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-1d-x/" title="Canon 1D X"> <img src="http://i.imgur.com/BlX05lN.png" class="attachment-kucuk wp-post-image" alt="Canon_EOS_1D_X_466261_i0"> <h4>Canon 1D X</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-7d-mark2/" title="Canon 7D Mark2"> <img src="http://i.imgur.com/DB3cfLX.png" class="attachment-kucuk wp-post-image" alt="_3962017"> <h4>Canon 7D Mark2</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-7d/" title="Canon 7D"> <img src="http://i.imgur.com/lOpicbY.png" class="attachment-kucuk wp-post-image" alt="Canon EOS 7D"> <h4>Canon 7D</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-70d/" title="Canon 70D"> <img src="http://i.imgur.com/GT0t4eo.png" class="attachment-kucuk wp-post-image" alt="Canon-eos-70-d-fotograf-makinesi"> <h4>Canon 70D</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-6d/" title="Canon 6D"> <img src="http://i.imgur.com/y2wRSZx.png" class="attachment-kucuk wp-post-image" alt="Canon 6D"> <h4>Canon 6D</h4> </a> </li> <li> <a href="http://127.0.0.1/makine/canon-ef-50mm-f1-8-ii/" title="Canon EF 50mm f/1.8 II"> <img src="http://i.imgur.com/5l2GjRG.png" class="attachment-kucuk wp-post-image" alt="Canon_EF_50mm_f18"> <h4>Canon EF 50mm f/1.8 II</h4> </a> </li> </ul> </div></div>，你可以这样做：

散列中的哈希修改问题，替换ruby中的值

3 个答案: