Question

这是我如何序列化一个对象。如何检索xml字符串以替换单引号？

var settings = new XmlWriterSettings {OmitXmlDeclaration = true};

            settings.Encoding = Encoding.ASCII;

            var writer = XmlWriter.Create(writeStream, settings);

            var serializer = new XmlSerializer(value.GetType());

            var nameSpaces = new XmlSerializerNamespaces();

            nameSpaces.Add(string.Empty, string.Empty);

            serializer.Serialize(writer, value, nameSpaces);

Answer 1

您可以序列化为文本编写器并执行必需的字符串操作，例如：

static void Main(string[] args)
{
    var value = new Class1() { SomeProperty = "content' asdasd' asdasd" };
    var settings = new XmlWriterSettings()
    {
        OmitXmlDeclaration = true,
        Encoding = Encoding.ASCII
    };
    var serializer = new XmlSerializer(typeof(Class1));
    string output = string.Empty;

    var nameSpaces = new XmlSerializerNamespaces();
    nameSpaces.Add(string.Empty, string.Empty);

    using (StringWriter textWriter = new StringWriter())
    {
        using (XmlWriter xmlWriter = XmlWriter.Create(textWriter, settings))
        {
            serializer.Serialize(xmlWriter, value, nameSpaces);
        }
        output = textWriter.ToString();
        Console.WriteLine(output);
    }

    string newOutput = output.Replace('\'', 'x');
    Console.WriteLine(newOutput);
}

在此示例中，输出为

<Class1><SomeProperty>content' asdasd' asdasd</SomeProperty></Class1>
<Class1><SomeProperty>contentx asdasdx asdasd</SomeProperty></Class1>

检索xml serialize输出字符串以替换单引号

1 个答案: