Question

我正在尝试在字符串中查找不是来自<img>的网址。例如：

$string = "lorem ipsum http://google.com dolor sit amet <img src="http://img.com/img.png" />;

要：

lorem ipsum http://google.com dolor坐下来＆LT; img src =＆＃34; http：//img.com/img.png" /＆gt;

我试过了：

function make_clickable($text) {
$regex = '#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#';
return preg_replace_callback($regex, function ($matches) {
    return "<p><a href='{$matches[0]}' class='link'>{$matches[0]}</a></p>";
}, $text);
$matches = array();

}

编辑：那可能是这样的：

function make_clickable($text) {
 $regex = '#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#';
 return preg_replace_callback($regex, function ($matches) {
    return "<p><a href='{$matches[0]}' class='link'>{$matches[0]}</a></p>";
 }, $text);
 $matches = array();
}

$string = preg_replace('/\bsrc="http\b/u', 'src="htt-p', $string);
$string = make_clickable($string);
$string = preg_replace('/\bsrc="htt-p\b/u', 'src="http', $string);
echo $string;

Answer 1

这样做。有关其工作原理的简短说明可在代码注释中找到：

<?php

# fixed syntax error string
$string = "lorem ipsum http://google.com dolor sit amet <img src=\"http://img.com/img.png\" />";

function make_clickable($text) {
    # explode string on spaces to array
    $arr = explode(' ', $text);

    # test each array element if it contains nothing else but a website
    foreach($arr as $key => $value){
        if(preg_match('#((^https?|ftp)://(\S*?\.\S*?))([\s)\[\]{},;"\':<]|\.\s|$)#i', $value)){
            # replace plain text urls with href links in array
            $arr[$key] = "<p><a href='". $value ."' class='link'>". $value ."</a></p>";
        }
    }

    # rebuild array back to string
    $text = implode(' ', $arr);

    # return result
    return $text;
}

echo make_clickable($string);

?>

在字符串而不是图像中查找链接URL

1 个答案: