我有两张表如下:
1. tbl_student:
id name
1 raj
2 raja
3 raju
4 rajan
tbl_attendance
id student_id month attended_days
1 1 1 6
2 1 2 16
3 8 1 8
4 7 2 14
5 8 2 13
6 7 1 11
我需要将这两个表连接起来,将每个学生的每一行从tbl_attendance组合成一行,以获得如下结果:
id name month attended_days month attended_days
1 raj 1 6 2 16
7 raja 1 11 2 14
8 rajan 1 8 2 13
提前感谢您的帮助。
答案 0 :(得分:2)
而不是在每个记录中显示月份值,
您可以将它们用作列标题和出勤率作为其值。
使用 pivot 类型解决方案来实现所需的解决方案。
示例:
select s.id as student_id
, s.name as student_name
, max( case when a.month = 1 then a.attended_days else null end ) as month_1
, max( case when a.month = 2 then a.attended_days else null end ) as month_2
, max( case when a.month = 3 then a.attended_days else null end ) as month_3
-- ...
, max( case when a.month = 12 then a.attended_days else null end ) as month_12
from table_student s
left join table_attendance a on s.id = a.student_id
group by s.id, s.name
答案 1 :(得分:0)
你的问题不是很完整,但我想你想要这样的事情:
select s.*,
coalesce(a1.month, a2.month, a3.month) as month,
coalesce(a1.attended_days , a2.attended_days , a3.attended_days ) as attended_days
from table_student s
left join table_attendance a1 on s.id = a1.student_id and a1.month = 1
left join table_attendance a2 on s.id = a2.student_id and a2.month = 2
left join table_attendance a3 on s.id = a3.student_id and a3.month = 3
如果要在一列中显示所有月份,则使用上一代码。对于多列,您可以使用以下示例:
select s.*,
a1.month as month_1,
a2.month as month_2,
a3.month as month_3,
a1.attended_days as attended_days_1,
a2.attended_days as attended_days_2,
a3.attended_days as attended_days_3
from table_student s
left join table_attendance a1 on s.id = a1.student_id and a1.month = 1
left join table_attendance a2 on s.id = a2.student_id and a2.month = 2
left join table_attendance a3 on s.id = a3.student_id and a3.month = 3
这12个月都这样做了。我以3为例。