在运行以下程序时,我收到错误
org.hibernate.MappingException:无法确定类型:java.util.Set,对于列:[org.hibernate.mapping.Column(ListOfAddress)]
我添加了import javax.persistence.ElementCollection;
但我得到了同样的错误
任何人都可以建议我任何选择吗?
HibernateTest.java
package src.com.hibernate.main;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.AnnotationConfiguration;
import org.hibernate.mapping.*;
import src.com.hibernate.Address;
import src.com.hibernate.UserDetails;
public class HibernateTest {
public static void main(String[] args)
{
UserDetails user = new UserDetails();
user.setUserName("Surendar");
Address addr = new Address();
addr.setStreet("Abith colony");
addr.setCity("Chennai");
addr.setState("TamilNAdu");
addr.setPincode("600015");
Address addr1= new Address();
addr1.setStreet("Anna Salai");
addr1.setCity("Chennaimain");
addr1.setState("TN");
addr1.setPincode("600033");
user.getListOfAddress().add(addr);
user.getListOfAddress().add(addr1);
SessionFactory sessionFactory = new AnnotationConfiguration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();
session.beginTransaction();
session.save(user);
session.getTransaction().commit();
session.close();
}
}
UserDetails.java
package src.com.hibernate;
import java.util.HashSet;
import java.util.Set;
import javax.persistence.ElementCollection;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name="UserTABLEaddress")
public class UserDetails
{
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private int userId;
private String userName;
@SuppressWarnings("rawtypes")
@ElementCollection
private Set<Address> ListOfAddress = new HashSet();
public Set<Address> getListOfAddress() {
return ListOfAddress;
}
public void setListOfAddress(Set<Address> listOfAddress) {
ListOfAddress = listOfAddress;
}
public int getUserId() {
return userId;
}
public void setUserId(int userId) {
this.userId = userId;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
Address.java
package src.com.hibernate;
import javax.persistence.Embeddable;
@Embeddable
public class Address
{
private String street;
private String city;
private String state;
private String pincode;
public String getStreet() {
return street;
}
public void setStreet(String street) {
this.street = street;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getState() {
return state;
}
public void setState(String state) {
this.state = state;
}
public String getPincode() {
return pincode;
}
public void setPincode(String pincode) {
this.pincode = pincode;
}
}
hibernate.cfg.xml中
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost:3306/hibernate</property>
<property name="connection.username">root</property>
<property name="connection.password"></property>
<property name="show_sql">true</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hbm2ddl.auto">create</property>
<mapping class="src.com.hibernate.UserDetails"/>
</session-factory>
</hibernate-configuration>
答案 0 :(得分:1)
我认为你们正在混合概念。您尝试在@Embeddable
关系中使用的类中使用many-to-one
注释。这是导致错误的原因。
如果要将ListOfAddress
用作元素集合,则必须将Address
定义为实体并正确配置关系,例如:
...
@ElementCollection
@CollectionTable(name="address", joinColumns=@JoinColumn(name="userId"))
@Column(name="addresses")
private Set<Address> ListOfAddress = new HashSet<Address>();
...
在地址类
@Entity
@Table(name="address")
public class Address
...
网上有很多例子。
答案 1 :(得分:0)
我遇到了类似的问题,当我将我的java编译器版本从1.6改为1.5时,它对我有用。
所以可能会检查你是否属于这种情况