生成角度未知标签

Question

我正在使用此代码进行选择：

为什么要生成此选项标记？

 <option value="? string:feminino ?"></option>

它只发生在：

1. 我从选择
中选择一个选项
2. 我使用性别
更新了网址
3. 然后刷新。 （尝试使用网址上的选项自动选择）
之前的

html：

  <select id="gender" ng-model="genderMarked" ng-change="updateGender(genderMarked)" >
                            <option value="">Select a gender</option>

                            <option ng-value="collection.slug" ng-repeat="collection in collectionsGender">{{collection.title}}</option>
                        </select>

之后的HTML：

     <select id="gender" ng-model="genderMarked" ng-change="updateGender(genderMarked)" class="ng-pristine ng-valid ng-touched"><option value="? string:feminino ?"></option>
            <option value="? string:feminino ?"></option>

            <option value="">Select a gender</option>

            <option ng-value="collection.slug" ng-repeat="collection in collectionsGender" class="ng-binding ng-scope" value="masculino">Masculino</option>

           <option ng-value="collection.slug" ng-repeat="collection in collectionsGender" class="ng-binding ng-scope" value="feminino">Feminino</option>

          <option ng-value="collection.slug" ng-repeat="collection in collectionsGender" class="ng-binding ng-scope" value="infantil">Infantil</option>
    </select>

我正在使用以下代码从网址（如果用户刷新页面）中获取性别标记：

       if($stateParams.genderSlug){
            $scope.genderMarked = $stateParams.genderSlug;
        }else{
            $scope.genderMarked =  '';
        }

Answer 1

我发现ng-options比重复的<option>代码更容易使用。

试试这个

<select id="gender" ng-model="genderMarked" ng-change="updateGender(genderMarked)"
        ng-options="collection.slug as collection.title for collection in collectionsGender">
    <option value="">Select a gender</option>
</select>