我有以下实体:
package model.entity;
import java.util.Set;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import com.fasterxml.jackson.annotation.JsonBackReference;
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.JsonManagedReference;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
@Entity
@JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="id")
public class Folder {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column
private String title;
@JsonBackReference
@ManyToOne(cascade = { CascadeType.ALL }, fetch = FetchType.EAGER)
@JoinColumn(name = "parent")
private Folder parent;
@JsonManagedReference
@OneToMany(mappedBy="parent")
private Set<Folder> children;
@JsonManagedReference
@OneToMany(mappedBy="containerFolder")
private Set<Project> projects;
@Column
private Integer orderIndex;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getTitle() {
return title;
}
public void setTitle(String name) {
this.title = name;
}
public Folder getParent() {
return parent;
}
public void setParent(Folder parent) {
this.parent = parent;
}
public Set<Folder> getChildren() {
return children;
}
public void setChildren(Set<Folder> children) {
this.children = children;
}
public Set<Project> getProjects() {
return projects;
}
public void setProjects(Set<Project> projects) {
this.projects = projects;
}
public Integer getOrderIndex() {
return orderIndex;
}
public void setOrderIndex(Integer orderIndex) {
this.orderIndex = orderIndex;
}
}
我使用Criteria API进行查询以查找父级的所有子级。
Session session = (Session) JPA.em().getDelegate();
List rootFolderList = session.createCriteria(Folder.class).add(Restrictions.isNull("parent")).list();
if (rootFolderList.isEmpty()) {
Folder root = new Folder();
root.setTitle("root");
JPA.em().persist(root);
rootFolder = root;
} else
rootFolder = (Folder) rootFolderList.get(0);
Criteria criteria = session.createCriteria(Folder.class);
criteria.add(Restrictions.eq("parent", rootFolder.getId()));
List<Folder> folders = criteria.list();
获取根元素的第一个查询不是问题。它找到根元素并且不会给出错误。但是,第二个查询会在 list()方法上抛出异常。
[PropertyAccessException: could not get a field value by reflection getter of model.entity.Folder.id]
除了例外,有几种解决方案,但它们对我不起作用:
答案 0 :(得分:0)
获取根元素的第一个查询不是问题
我对此表示怀疑,因为查询试图找到所有没有ID的文件夹(并且显然都有一个:一个实体在没有ID的情况下不存在)。实际应该做的是找到没有父母的实体。这将为您提供根文件夹。
然后你做
criteria.add(Restrictions.eq("parent", rootFolder.getId()));
类型为Folder的父级如何等于类型为Long的rootFolder.getId()?
你想要的是
criteria.add(Restrictions.eq("parent", rootFolder));
或
criteria.add(Restrictions.eq("parent.id", rootFolder.getId()));