我有这个代码片段来获取同义词(我从其中一个帖子中得到了它)。我想在列表中获取同义词,而不是打印如下所示
from nltk.corpus import wordnet as wn
import nltk
from nltk.corpus.reader.plaintext import PlaintextCorpusReader
def me():
T = []
for i,j in enumerate(wn.synsets('small')):
#print "Synonyms:", ", ".join(j.lemma_names())
for item in [", ".join(j.lemma_names())]:
print T.append(item)
如果我使用:
print item
,
我得到了这个答案:
small
small
small, little
minor, modest, small, small-scale, pocket-size, pocket-sized
little, small
small
humble, low, lowly, modest, small
little, minuscule, small
little, small
small
modest, small
belittled, diminished, small
small
如果我使用
print T.append(item)
,
我明白了:
None
None
None
None
None
None
None
None
None
None
None
None
None
我想要的是:
[ small, little, minor, modest, small-scale, pocket-size, pocket-sized, humble, low, lowly, minuscule, belittled, diminished]
答案 0 :(得分:2)
T.append(item)
将item
添加到列表中并返回None
。如果我理解正确,你想看到列表增长(对吧?)。然后你可以试试这个:
for item in [", ".join(j.lemma_names())]:
T.append(item)
print T
或(也许更好); {/ 1}}在您的方法结束时使用它:
return T