Question

下面的代码用于排序字符串数组，如果它们都是小写或全部大写但我想在排序时忽略大小写。我怎么能这样做？以下是自定义类的数组。

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Answer 1

您可以使用String方法localizedCompare（）

更新： Xcode 8.2•Swift 3.0.2

let array = ["def","Ghi","Abc" ]

let sorted1 = array.sorted{$0.compare($1) == .orderedAscending}
print(sorted1)  // ["Abc", "Ghi", "def"]

let sorted2 = array.sorted{$0.localizedCompare($1) == .orderedAscending}
print(sorted2) // ["Abc", "def", "Ghi"]


// you can also use the String compare options parameter to give you more control when comparing your strings
let sorted3 = array.sorted{$0.compare($1, options: .caseInsensitive) == .orderedAscending }
print(sorted3)   // ["Abc", "def", "Ghi"]\n"

// which can be simplifyed using the string method caseInsensitiveCompare
let sorted4 = array.sorted{$0.caseInsensitiveCompare($1) == .orderedAscending}
print(sorted4) // ["Abc", "def", "Ghi"]\n"

// or localized caseInsensitiveCompare
let array5 = ["Cafe B","Café C","Café A"]
let sorted5 = array5.sorted{$0.localizedCaseInsensitiveCompare($1) == .orderedAscending}
print(sorted5) // "["Café A", "Cafe B", "Café C"]\n"

Answer 2

您可以将String转换为小写，然后进行比较：

array.sort{ $0.lowercaseString < $1.lowercaseString }

Answer 3

以下an answer about overriding compareTo in Java更改sort命令的方式。如果将字符串转换为大写，然后比较它们会发生什么？

Answer 4

这是应该使用的方法，用于此目的：

public func caseInsensitiveCompare(aString: String) -> NSComparisonResult

在你的情况下：

resultListArray.sort({ $0.fileName.caseInsensitiveCompare($1.fileName) == NSComparisonResult.OrderedAscending })

Answer 5

var items = ["a","A","b","B","c","C","d","D"] 
items = items.sorted(by: { (item1, item2) -> Bool in
     return item1.localizedCompare(item2) == .orderedAscending
})

对String数组进行排序并忽略大小写

5 个答案: