Question

想象一下，我有一个字符串 - 像这样：

This is some really cool text about http://google.com/ and it also contains some urls like http://apple.com/ and its very nice! This is too long and I need to do some magic stuff to fix this very big problem. Oh no.

正如你所看到的，字符串中有两个URL，不知何故，假设我需要某种REGEX，我需要获取这些URL的数组，以便我可以操作它们。像这样......

Array()

- [0] = 'http://google.com/'
- [1] = 'http://apple.com/'

所有帮助赞赏:) 谢谢！

Answer 1

https?:\/\/[^\s]+

找到以http：//或https：//开头的内容，然后拉出字符直到找到空格。

Answer 2

我认为这也应该有用。

$string = 'ajskldfj http://google.ca jslfkjals s http://www.apple.com jalksf';
$pattern = '/[A-Za-z]+:\/\/[A-Za-z0-9-_]+\.[A-Za-z0-9-_:%&\?\/.=]+/';
preg_match_all($pattern, $string, $matches);

Answer 3

您需要一个如下所示的正则表达式模式：

'https?:\/\/(\w*?.)?(?P<domain>\w+).(\w+)/'

解析字符串以获取URL数组

3 个答案: