我是新手。我想将我的Android应用程序连接到wampserver数据库。我找到了关于这个link的教程,但是我应该在哪里找到我在wampserver中的serverUrl?它应如下所示:private final String serverUrl = "your path here"
那么我在哪里可以找到"your path here"
?
这是我的代码:
MainActivity.java
package inducesmile.com.androidloginandregistration;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.params.BasicHttpParams;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
public class MainActivity extends ActionBarActivity {
protected EditText username;
private EditText password;
protected String enteredUsername;
private final String serverUrl = "your path here";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
username = (EditText)findViewById(R.id.username_field);
password = (EditText)findViewById(R.id.password_field);
Button loginButton = (Button)findViewById(R.id.login);
Button registerButton = (Button)findViewById(R.id.register_button);
loginButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
enteredUsername = username.getText().toString();
String enteredPassword = password.getText().toString();
if(enteredUsername.equals("") || enteredPassword.equals("")){
Toast.makeText(MainActivity.this, "Username or password must be filled", Toast.LENGTH_LONG).show();
return;
}
if(enteredUsername.length() <= 1 || enteredPassword.length() <= 1){
Toast.makeText(MainActivity.this, "Username or password length must be greater than one", Toast.LENGTH_LONG).show();
return;
// request authentication with remote server4
AsyncDataClass asyncRequestObject = new AsyncDataClass();
asyncRequestObject.execute(serverUrl, enteredUsername, enteredPassword);
}
});
registerButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent = new Intent(MainActivity.this, RegisterActivity.class);
startActivity(intent);
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
private class AsyncDataClass extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
HttpParams httpParameters = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParameters, 5000);
HttpConnectionParams.setSoTimeout(httpParameters, 5000);
HttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpPost httpPost = new HttpPost(params[0]);
String jsonResult = "";
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", params[1]));
nameValuePairs.add(new BasicNameValuePair("password", params[2]));
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
jsonResult = inputStreamToString(response.getEntity().getContent()).toString();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return jsonResult;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
System.out.println("Resulted Value: " + result);
if(result.equals("") || result == null){
Toast.makeText(MainActivity.this, "Server connection failed", Toast.LENGTH_LONG).show();
return;
}
int jsonResult = returnParsedJsonObject(result);
if(jsonResult == 0){
Toast.makeText(MainActivity.this, "Invalid username or password", Toast.LENGTH_LONG).show();
return;
}
if(jsonResult == 1){
Intent intent = new Intent(MainActivity.this, LoginActivity.class);
intent.putExtra("USERNAME", enteredUsername);
intent.putExtra("MESSAGE", "You have been successfully login");
startActivity(intent);
}
}
private StringBuilder inputStreamToString(InputStream is) {
String rLine = "";
StringBuilder answer = new StringBuilder();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
try {
while ((rLine = br.readLine()) != null) {
answer.append(rLine);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return answer;
}
}
private int returnParsedJsonObject(String result){
JSONObject resultObject = null;
int returnedResult = 0;
try {
resultObject = new JSONObject(result);
returnedResult = resultObject.getInt("success");
} catch (JSONException e) {
e.printStackTrace();
}
return returnedResult;
}
}
我正在使用带有user="root"
和password=""
答案 0 :(得分:2)
感谢 @ e4c5 (针对建议)和 @Laser 的答案。
我解决了!
因此对于偶然发现此问题的其他人来说,检查一下! ^ _ ^
转到 cmd &gt;&gt;输入ipconfig
&gt;&gt;然后查看 IPv4地址 ...
然后将其粘贴到private final String serverUrl = "your path here"
将your path here
替换为http://192.168.1.8/android_user_api/index.php
谢谢你们!
快乐的编码!
答案 1 :(得分:1)
&#34;路径&#34;可能是本地Web服务器的URL,即:
http://your_ip/your_path_to_your_php_script
答案 2 :(得分:0)
您需要找到计算机的IPV4地址,在计算机中运行命令提示符(转到Windows启动按钮并启动typig cmd)并输入ipconfig并输入以查看计算机的IPV4地址。
在计算机上成功运行WAMP服务器会在系统托盘上显示绿色图标,单击该图标,弹出菜单,单击 put online 项。等待几秒钟来处理它的任务。
要在Android工作室模拟器中测试PHP MySQL的应用程序,只需输入地址http:\\IP Address\
,然后在代码中输入PHP文件的路径。
例如:http:\\192.168.1.7\test\example.php
答案 3 :(得分:0)
对我有用的解决方案是在我正在开发的android应用中使用10.0.2.2作为IP地址。