Question

我正在尝试在Django项目中创建一个slug字段。但是，在尝试访问django admin上的类别时，我一直收到此错误，我是Django的新手，只是想跟上教程。

+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Table          | Create Table                                                                                                                                                                                                                                                                   |
+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| rango_category | CREATE TABLE `rango_category` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(128) NOT NULL,
  `likes` int(11) NOT NULL,
  `views` int(11) NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1 |
+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

Models.py文件

from django.db import models
from django.template.defaultfilters import slugify

# Create your models here.
class Category(models.Model):
    name = models.CharField(max_length=128, unique=True)
    views = models.IntegerField(default=0)
    likes = models.IntegerField(default=0)
    slug = models.SlugField(unique=True)

    class Meta:
            verbose_name_plural = "Categories"


    def save(self, *args, **kwargs):
            self.slug = slugify(self.name)
            super(Category, self).save(*args, **kwargs)

    def __unicode__(self):
            return self.name

class Page(models.Model):
    category = models.ForeignKey(Category)
    title = models.CharField(max_length=128)
    url = models.URLField()
    views = models.IntegerField(default=0)

    def __unicode__(self):
            return self.title

Answer 1

如您所见，您slug表中没有rango_category字段。

在rango_category表的相应模型中，假设RangoCategory模型添加一个slug字段：

class RangoCategory(models.Model):
    id = ...
    likes = ...
    name = ...
    views = ...
    slug = models.SlugField()

然后运行python manage.py makemigrations和python manage.py migrate，它可能会要求设置为现有行的值。

这将在你的db表中创建一个slug字段。

我（1054，'字段列表'中的“未知列'rango_category.slug'”）Django

1 个答案: