Question

我在Oracle DB中有一个表

|SHIFT|     START_TIME (TIMESTAMP)     |      END_TIME (TIMESTAMP)      |
|  2  |  01-AUG-15 11.00.00.000000 PM  |  02-AUG-15 08.00.00.000000 AM  |
|  4  |  01-AUG-15 07.00.00.000000 AM  |  01-AUG-15 04.00.00.000000 PM  | 
|  3  |  01-AUG-15 02.00.00.000000 AM  |  01-AUG-15 11.00.00.000000 AM  | 
|  1  |  01-AUG-15 02.00.00.000000 PM  |  01-AUG-15 11.00.00.000000 PM  | 
|  5  |  01-AUG-15 08.30.00.000000 AM  |  01-AUG-15 05.30.00.000000 PM  |

我希望返回对应于特定时间戳的那些行。运行以下查询有效：

select shift, 
  cast(start_time as time), 
  cast(end_time as time)
from mytable 
where cast('12.00.00.000000 PM' as time) 
  between cast(start_time as time) and
  cast(end_time as time);

但是，相同的查询不适用于演员表（＆＃39; 12.00.00.000000 AM ＆＃39;作为时间）即以下查询不起作用。它返回0行。我做错了什么？

select shift, 
  cast(start_time as time), 
  cast(end_time as time)
from mytable 
where cast('12.00.00.000000 AM' as time) 
  between cast(start_time as time) and
  cast(end_time as time);

我甚至试过start_time和start_time + 9hours之间的匹配，但是得到了相同的行为。

select shift,
cast(start_time as time), 
cast((start_time + numtodsinterval(9,'HOUR')) as time) 
from ata_ipd_web_shifts where cast('12.00.00.000000 PM' as time) 
BETWEEN  cast(start_time as time) AND 
cast((start_time + numtodsinterval(9,'HOUR')) as time);

那么这里的问题是什么？提取所需行的最佳方法是什么？

Answer 1

制作想要检查INTERVAL的时间并将其添加到班次的开始日期和班次的结束日期。像这样：

with d as ( SELECT 2 shift, to_timestamp('01-AUG-15 11.00.00.000000 PM') start_date, to_timestamp('02-AUG-15 08.00.00.000000 AM') end_date from dual
UNION ALL SELECT 4 shift, to_timestamp('01-AUG-15 07.00.00.000000 AM'), to_timestamp('01-AUG-15 04.00.00.000000 PM') from dual
UNION ALL SELECT 3 shift, to_timestamp('01-AUG-15 02.00.00.000000 AM'), to_timestamp('01-AUG-15 11.00.00.000000 AM') from dual
UNION ALL SELECT 1 shift, to_timestamp('01-AUG-15 02.00.00.000000 PM'), to_timestamp('01-AUG-15 11.00.00.000000 PM') from dual
UNION ALL SELECT 5 shift, to_timestamp('01-AUG-15 08.30.00.000000 AM'), to_timestamp('01-AUG-15 05.30.00.000000 PM') from dual
)
select * from d
where trunc(start_date)+TO_DSINTERVAL('0 09:00:00') between start_date and end_date
OR trunc(end_date)+TO_DSINTERVAL('0 09:00:00') between start_date and end_date

请注意，间隔是24小时制，因此午夜（您在示例中使用的）是0 00:00:00。

Oracle SQL语句，用于查找两个时间戳列之间具有输入时间戳的行

1 个答案: