Question

我有一个我做过的平均程序，我试图只允许它接受数字。其他一切都有效，但我似乎无法弄明白。我还在学习，任何建议或指针都会很棒！

这是我的代码。

import java.util.Scanner;

public class THISISATEST {
    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        int sum = 0;
        int count = 0;
        int i = 1;
        while (i <= 10) {
            i++;

            {
                System.out.print("Enter the test score: ");
                int tS = keyboard.nextInt();
                count++;
                sum = (sum + tS);
            }
            System.out.println(sum);
        }

        System.out.println("The Average is = " + sum / count);
    }
}

Answer 1

在while循环中使用以下代码：

System.out.print("Enter the test score: ");
while (!keyboard.hasNextInt()) {//Will run till an integer input is found
    System.out.println("Only number input is allowed!");
    System.out.print("Enter the test score: ");
    keyboard.next();
}
int tS = keyboard.nextInt();
//If input is a valid int value then the above while loop would not be executed   
//but it will be assigned to your variable 'int ts'
count++;

sum = (sum + tS);

仅允许从java中的用户输入中获取数字

1 个答案: