好的,我所拥有的是一系列县。我想做的是按县获得客户数量。但是,我只需要三个主要县,然后将其他所有类别分组为“其他”类别。
select county,COUNT(*)
from person
where person_id in (select distinct person_id from person_encounter)
and create_timestamp >= CONVERT(datetime,'2015-08-01')
and create_timestamp <= CONVERT(datetime,'2015-08-31')
group by county
我拥有的东西让我对所有县的数量都很好。但是如何将额外内容分组为“其他”
答案 0 :(得分:2)
试试这个
select
CASE county
WHEN 'County1' THEN 'County1'
WHEN 'County2' THEN 'County2'
WHEN 'County3' THEN 'County3'
ELSE 'Other' END AS County
,COUNT(*)
from person
where person_id in (select distinct person_id from person_encounter)
and create_timestamp >= CONVERT(datetime,'2015-08-01')
and create_timestamp <= CONVERT(datetime,'2015-08-31')
group by
CASE county
WHEN 'County1' THEN 'County1'
WHEN 'County2' THEN 'County2'
WHEN 'County3' THEN 'County3'
ELSE 'Other' END ;
答案 1 :(得分:0)
如果一个UNION of 2查询1st =你的主要3个县,第二个=一切不是你的主要3个县
select * from student
where
(
(if studentId is not null then studentId='x')
else
(firstName='abc' and age > 26)
)