我有一个包含字段的表:
Parent引用同一个表中的主键ID(不是外键)。
+----+--------+------------+
| ID | Parent | Title |
+----+--------+------------+
| 1 | 0 | Wallpapers |
| 2 | 1 | Nature |
| 3 | 2 | Trees |
| 4 | 3 | Leaves |
+----+--------+------------+
我正在尝试选择一行及其所有父项。例如,如果我选择“离开”,我想要获得“树”,“自然”和“壁纸”,因为这是层次结构中的父路径。这可能在一个查询中?目前我在ColdFusion中使用循环来获取每次迭代的下一个父级,但它不够高效。
答案 0 :(得分:1)
您必须使用自联接来实现此目的: -
SELECT T1.Title AS CHILD, T2.Title AS PARENT
FROM YOUR_TABLE T1, YOUR_TABLE T2
WHERE T1.PARENT = T2.ID
AND T1.Title = 'Leaves'
答案 1 :(得分:0)
在PHP中,我编写了一个函数,用于检索路由表的所有层次结构(无限深度)。
我认为,在此示例中,您可以看到要查找的查询的SQL语法。除小写字母外,我使用相同的列名。
function get_breadcrumb($route_id) {
//access PDO mysql object instance
global $db;
// sanitize route ID
$route_id = intval($route_id);
// query construction
$q = "SELECT T2.*
FROM (
SELECT
@r AS parent_id,
(SELECT @r := `parent` FROM `route` WHERE id = parent_id) AS `parent`,
@l := @l + 1 AS `depth`
FROM
(SELECT @r := $route_id, @l := 0) vars,
`route` T3
WHERE @r <> 0) T1
JOIN `route` T2
ON T1.parent_id = T2.id
ORDER BY T1.`depth` DESC";
// call query in database
if($res = $db->query($q)) {
if($res = $res->fetchAll(PDO::FETCH_ASSOC)) {
if($size = sizeof($res) > 0) {
// push results in breadcrumb items array
$breadcrumb['items'] = $res;
$breadcrumb['levels'] = $size;
// retrieve only titles
$titles = array_column($res, 'title');
// construct html result seperated by '>' or '/'
$breadcrumb['html']['gt'] = implode(' > ', $titles);
$breadcrumb['html']['sl'] = implode(' / ', $titles);
// returns all result (added in SESSION too)
return $_SESSION['app']['breadcrumb'] = $breadcrumb;
}
}
}
// no result for that route ID
return false;
}
答案 2 :(得分:-1)
试试这个
SELECT
DISTINCT c.id AS 'ID', c.title AS 'Name'
FROM YourTable c, YourTable p
WHERE c.id = p.parent AND c.title = 'Leaves'
答案 3 :(得分:-1)
使用UNION将返回主行的查询与返回父行的另一个查询组合在一起。
SELECT *
FROM YourTable
WHERE Title = "Leaves"
UNION
SELECT t1.*
FROM YourTable AS t1
JOIN YourTable AS t2 ON t1.id = t2.parent
WHERE t2.Title = "Leaves")