Question

我无法将数据插入数据库'justrated'。一旦用户输入了他们的商业名称，它应该在表'business'中创建一个新条目。出于某种原因，我无法得到它，以便在表格中输入数据。任何建议都很高兴。

CODE：

<!DOCTYPE html>
<html>
<head>
    <title>Test</title>
</head>
<body>
<form>

<input type="text" name="BusinessName" method="POST">
<input type="Submit" value="submit" name="submit" method="POST">

</form>

<?php


if (isset($_POST["submit"])){
    //create connection
    $conn = new mysqli("localhost", "root", "", "justrated");
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }

    $sql = "INSERT INTO businesses (BusinessName)
VALUES ('".$_POST['BusinessName']."' )";
    mysql_query($sql);
    if ($conn->query($sql) === TRUE) {
        echo "New record created successfully";
    } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
    }

    $conn->close();
}

?>

</body>
</html>

Answer 1

您的一个问题是$_POST['BusinessName']为空，因为表单是使用GET请求而非POST请求提交的。 method=POST元素位于<form>元素上。例如：

<form method="POST">
  <input type="text" name="BusinessName">
  <input type="Submit" value="submit" name="submit">
</form>

此外，在将数据插入数据库之前，您应该正确地转义数据：

$sql = "INSERT INTO businesses (BusinessName)
VALUES ('" . $conn->real_escape_string ($_POST['BusinessName']) . "' )";

此外，在这两行中：

mysql_query($sql);
if ($conn->query($sql) === TRUE) {

您尝试使用MySQL和MySQLi扩展两次执行相同的查询。你应该删除第一行。

Answer 2

Html：

<form method="POST">

    <input type="text" name="BusinessName">
    <input type="Submit" value="submit" name="submit" >

    </form>

腓：使用

$conn->query($sql); not mysql_query()

Answer 3

HTML代码

<form method="post" action="test1.php">
<input type="text" name="BusinessName" >
<input type="Submit" value="submit" name="submit" >
</form>

PHP代码

if (isset($_POST["submit"]))
{
    //create connection 
    $conn = new mysqli("localhost", "root", "", "justrated");
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }

    $sql = "INSERT INTO businesses (`BusinessName`)
        VALUES ('".$_POST['BusinessName']."' )";

    if ($conn->query($sql) === TRUE) {
        echo "New record created successfully";
    } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
    }
    $conn->close();
}

不要混用mysql＆amp; mysqli ...

Answer 4

您好，请检查一下，希望这对您有用

$sql = "INSERT INTO businesses (`BusinessName`)
        VALUES ('".$_POST['BusinessName']."' )";

if (mysqli_query($conn, $sql)) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

将数据插入MYSQL数据库

4 个答案: