Question

我有以下XML页面结构：

<address>
<city>Anaheim</city>
<state>California</state>
<zip>92801</zip>
<country>United States</country>
</address>

<address>
<city>Berkley</city>
<state>California</state>
<zip>94705</zip>
<country>United States</country>
</address>

我想只获取城市标签的值，其中zip标签值符合条件。例如，我需要那些城市名称，其中zip = 92801。

python中有一种简单的方法可以做到这一点吗？

Answer 1

这将达到预期的效果：

my_string = '''
  <root>
    <address>
      <city>Anaheim</city>
      <state>California</state>
      <zip>92801</zip>
      <country>United States</country>
    </address>
    <address>
      <city>Berkley</city>
      <state>California</state>
      <zip>94705</zip>
      <country>United States</country>
    </address>
  </root>
'''

from lxml import etree

root = etree.fromstring(my_string)
cities = root.xpath('.//zip[text()="92801"]/preceding-sibling::city')

Answer 2

你如何使用ElementTree

import xml.etree.ElementTree as ET  
tree = ET.parse('country_data.xml')
root = tree.getroot()

filtered_addresses = []
for address in root.findall('address'):
    if address.get('zip') == '92801':
        filtered_addresses.append(address)

Answer 3

如果你想改用美丽的汤：

my_string = '''
<root>
  <address>
    <city>Anaheim</city>
    <state>California</state>
    <zip>92801</zip>
    <country>United States</country>
  </address>
  <address>
    <city>Berkley</city>
    <state>California</state>
    <zip>94705</zip>
    <country>United States</country>
  </address>
</root>
'''

from bs4 import BeautifulSoup
soup = BeautifulSoup(my_string, 'html.parser')
desired_zips = soup.findAll('zip', text="92801")
cities = []
for zip_tag in desired_zips:
    cities.append(zip_tag.findPreviousSibling('city'))

print(cities)

<强>输出：

[<city>Anaheim</city>]

注意：您可以将此for循环写入列表推导，但它看起来很笨重且不可读。

查找元素的特定兄弟

3 个答案: