Question

我有很多时间在思考如何解决，这是我的功能：

private String TextAlignCenter(String Line)
{
    String CenterLine = String.Empty;

    if (Line.Length > 36)
    {
        for (int i = 0; i < Line.Length; i += 36)
        {
            if ((i + 36) < Line.Length)
                TextAlignCenter(Line.Substring(i, 36));
            else
                TextAlignCenter(Line.Substring(i));
        }
    }
    else
    {
        Int32 CountLineSpaces = (int)(36 - Line.Length) / 2;
        for (int i = 0; i < CountLineSpaces; i++)
        {
            CenterLine += (Char)32;
        }
        CenterLine += Line;
    }
    Console.WriteLine(CenterLine);
    return CenterLine;
}

此函数将一个字符串拆分为36个字符的部分字符，然后使用空格添加结果字符以生成居中文本：例如：

string x = "27 Calle, Col. Ciudad Nueva, San Pedro Sula, Cortes";
TextAlignCenter(x);

结果：

Line1: 27 Calle, Col. Ciudad Nueva, San Ped
Line2:          ro Sula, Cortes
Line3:[EmptyLine]

Line1和Line2是正确的，但我不需要Line3，我怎么能阻止打印这条不必要的线？

更新

这些行被添加到ArrayList（）

中

ArrayList Lines = new ArrayList();
string x = "27 Calle, Col. Ciudad Nueva, San Pedro Sula, Cortes";
Lines.Add(TextAlignCenter(x));
Console.WriteLine(Lines.Count);

Answer 1

您需要的是完整块的循环以及 last 的特殊条件：

    public static IEnumerable<String> SplitByLength(String value, 
      int size, // you may want to set default for size, i.e. "size = 36"
      Char padding = ' ') {

      if (String.IsNullOrEmpty(value)) 
        yield break; // or throw an exception or return new String(padding, size);

      if (size <= 0)
        throw new ArgumentOutOfRangeException("size", "size must be a positive value");

      // full chunks with "size" length
      for (int i = 0; i < value.Length / size; ++i)
        yield return value.Substring(i * size, size);

      // the last chunk (if it exists) should be padded
      if (value.Length % size > 0) {
        String chunk = value.Substring(value.Length / size * size);

        yield return new String(padding, (size - chunk.Length) / 2) + 
          chunk + 
          new String(padding, (size - chunk.Length + 1) / 2);
      }
    }
...

String source = "27 Calle, Col. Ciudad Nueva, San Pedro Sula, Cortes";

// I've set padding to '*' in order to show it
// 27 Calle, 
// Col. Ciuda
// d Nueva, S
// an Pedro S
// ula, Corte
// ****s*****
Console.Write(String.Join(Environment.NewLine,
  SplitByLength(source, 10, '*')));

您的样本：

  string x = "27 Calle, Col. Ciudad Nueva, San Pedro Sula, Cortes";
  List<String> lines = SplitByLength(x, 36).ToList();

Answer 2

你不需要这里的递归函数。一些操作也不是最佳的

data Curve = Curve Point [Point]

fiddle demo

Answer 3

我会选择Console.Write：

private void TextAlignCenter(String Line)
{
    String CenterLine = String.Empty;

    if (Line.Length > 36)
    {
        for (int i = 0; i < Line.Length; i += 36)
        {
            if ((i + 36) < Line.Length)
                TextAlignCenter(Line.Substring(i, 36));
            else
                TextAlignCenter(Line.Substring(i));
        }
    }
    else
    {
        Int32 CountLineSpaces = (36 - Line.Length) / 2;
        for (int i = 0; i < CountLineSpaces; i++)
        {
            CenterLine += (Char)32;
        }
        CenterLine += Line + Environment.NewLine;
    }
    Console.Write(CenterLine);
}

使用maxchar居中和拆分字符串

3 个答案: