在我的html表单中有4个文本框和2个按钮previous
和next
我希望在用户单击form.and
按钮时在next
中显示表记录,下一条记录应在文本框中获取。
请帮帮我们
提前谢谢
答案 0 :(得分:0)
<?php
$id = 0;
if(isset($_POST['next']))
{
$id=$id++;
$que = mysql_query("select * from table where id ='$id'");
$data = mysql_fetch_array();
$data1 = $data[1];
$data1 = $data[2];
$data1 = $data[3];
$data1 = $data[4];
}
if(isset($_POST['prev']))
{
$id=$id--;
mysql_fetch_array(select * from table where id ='$id')
$data1 = $data[1];
$data1 = $data[2];
$data1 = $data[3];
$data1 = $data[4];
}
?>
<form method = "post">
<button name="prev">
<input type="text" value="$data1">
<input type="text" value="$data2">
<input type="text" value="$data3">
<input type="text" value="$data4">
<button name="next">
</form>