Question

这是我的代码，我必须附加一个字符串，以便我可以像 name，email，phoneNumber 那样输出，这是我想的两种方式

String matchedFields = "";
        DuplicateApplicantPojo duplicateApplicantPojo = new DuplicateApplicantPojo();
        if (applicant.getApplicantName().equals(detectionPojo.getName())) {
        matchedFields = DuplicateSettingsConstants.LABEL_NAME;
        }
        if (applicant.getApplicantEmail1().equals(detectionPojo.getEmail1())) {
        matchedFields = ", " + DuplicateSettingsConstants.LABEL_EMAIL;
        }
        if (applicant.getApplicantCellPhone().equals(detectionPojo.getCellPhone())) {
        matchedFields = ", " + DuplicateSettingsConstants.LABEL_PHONE;
        }

另一种方式是

 String matchedFields[] = new String[3];
        int i=0;
        DuplicateApplicantPojo duplicateApplicantPojo = new DuplicateApplicantPojo();
        if (applicant.getApplicantName().equals(detectionPojo.getName())) {
        matchedFields[i] = DuplicateSettingsConstants.LABEL_NAME;
        i++;
        }
        if (applicant.getApplicantEmail1().equals(detectionPojo.getEmail1())) {
        matchedFields[i] = DuplicateSettingsConstants.LABEL_EMAIL;
        i++;
        }
        if (applicant.getApplicantCellPhone().equals(detectionPojo.getCellPhone())) {
        matchedFields[i] =   DuplicateSettingsConstants.LABEL_PHONE;
        }
        String matched=matchedFields[0];
        for(int j=1;j<matchedFields.length;j++)
        {
        matched=", "+matchedFields[i];
        }

我更喜欢哪种方式？还是有其他办法我可以继续

Answer 1

您的代码不需要做额外的事情。第一种方法就足够了。

第二种方法的时间复杂度和空间复杂度都会更大。（虽然差异非常小）

Answer 2

好吧，它们都不会起作用，因为你要覆盖之前的值，而不是只是在最后附加字符串。我会在if测试中执行它，因为那时你不会将内存分配给数组然后跟踪一个额外的int。如果你使用for循环方式使用字符串构建器会更好，请参阅：when to use StringBuilder in java

Answer 3

第一个应该这样做，除了你可以使用StringBuilder附加“matchedFields”

StringBuilder matchedFields = new StringBuilder();
DuplicateApplicantPojo duplicateApplicantPojo = new DuplicateApplicantPojo();
if (applicant.getApplicantName().equals(detectionPojo.getName())) {
   matchedFields.append(DuplicateSettingsConstants.LABEL_NAME);
}if (applicant.getApplicantEmail1().equals(detectionPojo.getEmail1())) {
   matchedFields.append(" , ").append (DuplicateSettingsConstants.LABEL_EMAIL);
}
  .
  .
  .

从API获取有关它的更多信息：http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html

Answer 4

我建议添加辅助方法：

private static String getMatched(String prefix, String s1, String s2, String label) {
    String matchedFields = "";
    if (s1.equals(s2)) {
         matchedFields = prefix + label;
    }
    return matchedFields;
}

然后你可以写（+ DuplicateSettingsConstants的静态导入）：

    String matchedFields = "";
    matchedFields += getMatched("", applicant.getApplicantName(), detectionPojo.getName(), LABEL_NAME);
    matchedFields += getMatched(", ", applicant.getApplicantEmail1(), detectionPojo.getEmail1(), LABEL_EMAIL);
    matchedFields += getMatched(", ", applicant.getApplicantCellPhone(), detectionPojo.getCellPhone(), LABEL_PHONE);

我应该使用for循环还是If条件

4 个答案: