如何使用ajax将视图模型传递给控制器?请参阅下面的JS函数CreateTable():
我的控制器:
public ActionResult Index()
{
var viewModel = new MyViewModel();
return View(viewModel);
}
[HttpPost]
public ActionResult Index(MyViewModel viewModel)
{
//CODE FOR GETTING STUFF HERE
return View(viewModel);
}
public JsonResult GetResult(JQueryDataTableParamModel param, MyViewModel viewModel)
{
//CODE FOR GETTING STUFF HERE
return Json(new
{
sEcho = param.sEcho,
aaData = viewModel.Data,
iTotalRecords = viewModel.Data.Rows.Count,
iTotalDisplayRecords = viewModel.DisplayRecords
}, JsonRequestBehavior.AllowGet);
}
这是datatables.net处理的ajax部分:
function CreateTable() {
var table = $('#dataTable').DataTable({
"deferRender": true,
"bServerSide": true,
"sAjaxSource": "@Url.Action("GetResult")",
"fnServerParams": function (aaData) {
//here's my problem: HOW CAN I PUSH MY WHOLE MODEL HERE?
aaData.push({ "name": "MyViewModel", "value": "@Model" });
},
"sPaginationType": "simple_numbers",
"bProcessing": true,
"oLanguage": { "sProcessing": "Loading..." },
"aoColumns": [
{ "sName": "Col1" },
{ "sName": "Col2" },
{ "sName": "Col3" },
{ "sName": "Col3" },
{ "sName": "Col4" },
{ "sName": "Col5" }
]
});
}
我的朋友告诉我,我也可以将整个模型从ajax传递给我的控制器,但我不知道该怎么做。请告知实施此更好的方法。谢谢。
答案 0 :(得分:0)
您可以使用@Html.Raw(JsonConvert.SerializeObject(Model))
序列化模型,以便您的功能如下所示:
"fnServerParams": function (aaData) {
aaData.push({ name: "viewModel", value: @Html.Raw(JsonConvert.SerializeObject(Model)) });
},
答案 1 :(得分:0)
只要你传递与你的模型具有相同属性的json对象,你应该安全回家,例如:
Model:
public class Language
{
public int ID { get; set; }
public string Language1{ get; set; }
public string Language2 { get; set; }
}
Ajax:
$.ajax({
url: '@Url.Action("Action", "Controller")',
type: "POST",
contentType: 'application/json',
data: JSON.stringify({
ID: 1,
Language1: "English",
Language2: "German",
}),
dataType: 'json',
success: function (data) {
alert(data)
}
});
答案 2 :(得分:0)
使用fnServerParams时,您使用aoData.push({ "name": "customParam1", "value": $('#param1').val() });
aoData.push({ "name": "customParam2", "value": $('#param2').val() });
将自定义参数发送到服务器。我不确定将整个模型作为单个参数传递,但您可以这样做:
param1
其中param2
和MyViewModel
是从jQuery选择器检索的模型属性。
您的控制器方法需要从查询字符串中检索这些参数。像这样:
创建一个代表自定义参数的模型(这基本上会在您的示例中复制public class MyCustomParamModel
{
public string customParam1 { get; set; }
public string customParam2 { get; set; }
}
):
public JsonResult GetResult(JQueryDataTableParamModel param)
{
NameValueCollection qs = HttpUtility.ParseQueryString(Request.QueryString.ToString());
var model = new MyCustomParamModel
{
customParam1 = qs["customParam1"],
customParam2 = qs["customParam2"],
}
在控制器中,解析查询字符串,获取自定义参数并将它们分配给模型
{{1}}
现在您已将模型数据存储在控制器中,您可以随意使用它。