Question

您好我正在尝试将图片文件上传到服务器。我已经使用jCrop在上传之前裁剪图片并使用画布来获取裁剪的图像坐标。我已经包含了控制器和jsp文件。但是我＆＃ 39;我无法使用ajax发送formdata。

AppController.java

@RequestMapping(value = "/upload", method = RequestMethod.POST)
public String handleFormUpload(@RequestParam("file") MultipartFile file, ModelMap model) throws IOException{
if (!file.isEmpty()) {
    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
     String name = auth.getName(); //get logged in username
     BufferedImage src = ImageIO.read(new ByteArrayInputStream(file.getBytes()));
     File destination = new File("/home/me/Desktop/"+name+".png");
     model.addAttribute("username", name);
     // something like C:/Users/tom/Documents/nameBasedOnSomeId.png
     ImageIO.write(src, "png", destination);
     //Save the id you have used to create the file name in the DB. You can retrieve the image in future with the ID.
    }else {
     System.out.println("file is empty");
    }
return "prefs";
}

prefs.jsp

<script type="text/javascript">
$(function(){
    $('.majorpoints').click(function(){
        $(this).find('.hiders').slideToggle();
    });
     $("#imgInp").change(function(){
         var c = $('.cropArea').Jcrop({

             onSelect: updateCoords,

                   bgOpacity:   .4,
                   setSelect:   [ 100, 100, 50, 50 ],
                   aspectRatio: 16 / 9
           });

         function readURL(input) {

                if (input.files && input.files[0]) {
                    var reader = new FileReader();

                    reader.onload = function (e) {
                        $('#blah').attr('src', e.target.result);
                    }

                    reader.readAsDataURL(input.files[0]);
                }
            }
            readURL(this);
        }); 

     $('#btnCrop').click(function () {
            var x1 = $('#x').val();
            var y1 = $('#y').val();
            var width = $('#w').val();
            var height = $('#h').val();
            var canvas = $("#canvas")[0];
            alert(x1+""+y1+""+""+width+""+height);
            var context = canvas.getContext('2d');
            var img = new Image();
            img.onload = function () {
                canvas.height = height;
                canvas.width = width;
                context.drawImage(img, x1, y1, width, height, 0, 0, width, height);
                $("#imgInp").val(canvas.toDataURL("image/jpeg")); 
            };

            var data = new FormData();
            data.append('file', dataURItoBlob(canvas.toDataURL("image/jpeg")));
            $.ajax({
                url: 'upload',
                data: data,
                contentType: false,
                processData: false,
                type: 'POST',
                success: function(data){
                    alert(data);
                }
            }); 

            img.src = $('#blah').attr('src');

        });
});
 function dataURItoBlob(dataURI) {
    // convert base64/URLEncoded data component to raw binary data held in a string
    var byteString;
    if (dataURI.split(',')[0].indexOf('base64') >= 0)
        byteString = atob(dataURI.split(',')[1]);
    else
        byteString = unescape(dataURI.split(',')[1]);

    // separate out the mime component
    var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0];

    // write the bytes of the string to a typed array
    var ia = new Uint8Array(byteString.length);
    for (var i = 0; i < byteString.length; i++) {
        ia[i] = byteString.charCodeAt(i);
    }

    return new Blob([ia], {type:mimeString});
}
function updateCoords(c)
  {
    console.log(c);
    $('#x').val(c.x);
    $('#y').val(c.y);
    $('#w').val(c.w);
    $('#h').val(c.h);
    $('#btnCrop').show();
  };
 </script>


<div id="myModal" class="modal fade" role="dialog">
      <div class="modal-dialog">

        <!-- Modal content-->
        <div class="modal-content">
          <div class="modal-header">
            <button type="button" class="close" data-dismiss="modal">&times;</button>
            <h4 class="modal-title">Modal Header</h4>
          </div>
          <div class="modal-body">
            <form method="POST" action="upload" enctype="multipart/form-data">
                Please select a file to upload : 
                <input type="file" name="file" class="file" id="imgInp" />
                <div class="cropArea">
                    <img id="blah" src="#" alt="your image" />
                </div>
                <input type="hidden" id="x" name="x" />
                <input type="hidden" id="y" name="y" />
                <input type="hidden" id="w" name="w" />
                <input type="hidden" id="h" name="h" />
                <canvas id="canvas" height="5" width="5"></canvas>

            </form>
             <input type="button" id="btnCrop" value="Crop" style="display: none" />
          </div>
          <div class="modal-footer">
            <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
          </div>
        </div>

      </div>
</div>

Answer 1

你错过了这个参数

enctype：＆＃39; multipart / form-data＆＃39;

$.ajax({
        url: 'upload',
        data: data,
        contentType: false,
        processData: false,
        enctype: 'multipart/form-data',
        type: 'POST',
        success: function(data){
                   alert(data);
                }
       });

你应该有这个

var data = new FormData();
data.append('file', jQuery('#imgInp')[0].files[0]);

而不是

jQuery.each(jQuery('#imgInp')[0].files, function(i,file) {
            data.append('file-'+i, file);
        });

后来编辑2：在函数dataURItoBlob（dataURI）中添加如下回调：

function dataURItoBlob(dataURI, callback) {
   ...
 callback();
}

然后在

$（＆＃39;＃btnCrop＆＃39;）。click（function（）{...

data.append('file', dataURItoBlob(canvas.toDataURL("image/jpeg", function(){
            $.ajax({
                url: 'upload',
                data: data,
                contentType: false,
                processData: false,
                type: 'POST',
                success: function(data){
                    alert(data);
                }
            }); 
  })));

这样，您确定在执行dataURItoBlob后进行ajax调用。

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1 个答案: