我有这个用于向上/向下拇指的jQuery:
jQuery函数:
$(document).ready(function() {
//####### on page load, retrive votes for each content
$.each( $('.voting_wrapper'), function(){
//retrive unique id from this voting_wrapper element
var unique_id = $(this).attr("id");
//prepare post content
post_data = {'unique_id':unique_id, 'vote':'fetch'};
//send our data to "vote_process.php" using jQuery $.post()
$.post('<?PHP echo SITE;?>controller/cm_vote.php', post_data, function(response) {
//retrive votes from server, replace each vote count text
$('#'+unique_id+' .up_votes').text(response.vote_up);
$('#'+unique_id+' .down_votes').text(response.vote_down);
},'json');
});
//####### on button click, get user vote and send it to vote_process.php using jQuery $.post().
$(".voting_wrapper .voting_btn").click(function (e) {
//get data-action or class name (down_button / up_button) of clicked element
var clicked_button = $(this).children().attr('data-action');
//get unique ID from voted parent element
var unique_id = $(this).parent().attr("id");
if(clicked_button==='down_button') //user disliked the content
{
//prepare post content
post_data = {'unique_id':unique_id, 'vote':'down'};
//send our data to "vote_process.php" using jQuery $.post()
$.post('<?PHP echo SITE;?>controller/cm_vote.php', post_data, function(data) {
//replace vote down count text with new values
$('#'+unique_id+' .down_votes').text(data);
//thank user for the dislike
alert("Thanks! Each Vote Counts, Even Dislikes!");
}).fail(function(err) {
//alert user about the HTTP server error
alert(err.statusText);
});
}
else if(clicked_button==='up_button') //user liked the content
{
//prepare post content
post_data = {'unique_id':unique_id, 'vote':'up'};
//send our data to "vote_process.php" using jQuery $.post()
$.post('<?PHP echo SITE;?>controller/cm_vote.php', post_data, function(data) {
//replace vote up count text with new values
$('#'+unique_id+' .up_votes').text(data);
//thank user for liking the content
alert("Thanks! For Liking This Content.");
}).fail(function(err) {
//alert user about the HTTP server error
alert(err.statusText);
});
}
});
//end
});
HTML CODE:
<div class="voting_wrapper" id="<?PHP echo $row['id'];?>">
<div class="btn-group">
<div class="voting_btn">
<button type="button" data-action="up_button" class="btn btn-success btn-xs"><i class="fa fa-thumbs-o-up"></i> <span class="up_votes">0</span></button>
</div>
<div class="voting_btn">
<button type="button" data-action="down_button" class="btn btn-danger btn-xs "><i class="fa fa-thumbs-o-down"></i> <span class="down_votes">0</span></button>
</div>
</div>
</div>
我使用bootstrap 3设计拇指按钮,并为data-action
和down_button
添加up_button
,并使用此行中的jQuery函数检查data-action
:var clicked_button = $(this).children().attr('data-action');
。
但是在行动中,我的jQuery功能无法与data-action
一起使用,也无法向下发送or
向上按钮。
如何解决这个问题?!
答案 0 :(得分:1)