我有字典,键作为模式,替换为值。每个模式都有一个捕获组。我想替换ONLY捕获组。我的尝试如下,但当然它取代了整个模式。我仅限于.NET 3.5。不确定我是否在正确的轨道上。
string xml = "abc def ghi blabla horse 123 jakljd alj ldkfj s;aljf kljf sdlkj flskdjflskdjlf lskjddhcn guffy";
Dictionary<string, string> substitutions = new Dictionary<string, string>
{
{"abc (.+) ghi", "AAA"},
{"kljf (.+) flskdjflskdjlf", "BBB"}
};
foreach(KeyValuePair<string, string> entry in substitutions)
{
xml = Regex.Replace(xml, entry.Key, delegate(Match m) { return m.Groups[1].Value; });
Console.WriteLine(xml);
}
最后一个字符串应该是这样的:
"abc AAA ghi blabla horse 123 jakljd alj ldkfj s;aljf BBB sdlkj flskdjflskdjlf lskjddhcn guffy"
答案 0 :(得分:1)
您需要使用lookarounds
。
"(?<=abc ).+(?= ghi)", "AAA"
这将使您能够替换所需的单词。您不需要捕获组
答案 1 :(得分:0)
使用正面loohbehind and lookaheads:
string xml = "abc def ghi blabla horse 123 jakljd alj ldkfj s;aljf kljf sdlkj flskdjflskdjlf lskjddhcn guffy";
Dictionary<string, string> substitutions = new Dictionary<string, string>
{
{@"(?<=abc\s).+(?=\sghi)", "AAA"},
{@"(?<=kljf\s).+(?=\sflskdjflskdjlf)", "BBB"}
};
foreach (KeyValuePair<string, string> entry in substitutions)
{
xml = Regex.Replace(xml, entry.Key, entry.Value);
Console.WriteLine(xml);
}
它们是零宽度断言,即,它们需要满足匹配,但不会包含在结果中。